Re: Solutions of an equation under complex form

*To*: mathgroup at smc.vnet.net*Subject*: [mg54535] Re: [mg54478] Solutions of an equation under complex form*From*: Pratik Desai <pdesai1 at umbc.edu>*Date*: Tue, 22 Feb 2005 04:24:15 -0500 (EST)*References*: <200502210844.DAA27204@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

Michaël Monerau wrote: >Hello, > >I'm running into a little problem under Mathematica 5.0 but I'm sure >people here will just take it as "too easy", but, well :) I just want >the solutions of the equation : > >x^2 + x + 1 == 0 > >under their complex form. > >So, I type : > >Solve [x^2 + x + 1 == 0, x] > >But I unfortunately get : >{ { {x -> -(-1)^(1/3) }, { x -> (-1)^(2/3) } } } > >And I'd prefer to obtain the more "readable" form : >-1/2 + I*1/2*Sqrt[3], -1/2 - I*1/2*Sqrt[3] > >that I would get under another system for instance. What special function >should I call to get this form under Mathematica ? > >Thanks for any help > > Try This y=x^2+x+1 s=Reduce[y==0,x] s[[1]]//ComplexExpand s[[2]]//ComplexExpand hope this helps Pratik Desai

**References**:**Solutions of an equation under complex form***From:*Michaël Monerau <mmonerau@gmail.com>