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MathGroup Archive 2005

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Re: Solutions of an equation under complex form

  • To: mathgroup at smc.vnet.net
  • Subject: [mg54543] Re: [mg54478] Solutions of an equation under complex form
  • From: "tgarza01 at prodigy.net.mx" <tgarza01 at prodigy.net.mx>
  • Date: Tue, 22 Feb 2005 04:24:59 -0500 (EST)
  • Reply-to: tgarza01 at prodigy.net.mx
  • Sender: owner-wri-mathgroup at wolfram.com

Try this:

In[1]:=
ComplexExpand@Solve [x^2 + x + 1 == 0, x][[#,1,2]]&/@{1,2}
Out[1]=
{-(1/2) - (I*Sqrt[3])/2, -(1/2) + (I*Sqrt[3])/2}

Tomas Garza
Mexico City

Original Message:
-----------------
From: Michaël Monerau mmonerau at gmail.com
To: mathgroup at smc.vnet.net
Subject: [mg54543] [mg54478] Solutions of an equation under complex form


Hello,

I'm running into a little problem under Mathematica 5.0 but I'm sure 
people here will just take it as "too easy", but, well :) I just want 
the solutions of the equation :

x^2 + x + 1 == 0

under their complex form.

So, I type :

Solve [x^2 + x + 1 == 0, x]

But I unfortunately get :
{ { {x -> -(-1)^(1/3) }, { x -> (-1)^(2/3) } } }

And I'd prefer to obtain the more "readable" form :
-1/2 + I*1/2*Sqrt[3], -1/2 - I*1/2*Sqrt[3]

that I would get under another system for instance. What special function
should I call to get this form under Mathematica ?

Thanks for any help
-- 
Michaël Monerau
-= JJG =-


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