Re: Solutions of an equation under complex form

*To*: mathgroup at smc.vnet.net*Subject*: [mg54543] Re: [mg54478] Solutions of an equation under complex form*From*: "tgarza01 at prodigy.net.mx" <tgarza01 at prodigy.net.mx>*Date*: Tue, 22 Feb 2005 04:24:59 -0500 (EST)*Reply-to*: tgarza01 at prodigy.net.mx*Sender*: owner-wri-mathgroup at wolfram.com

Try this: In[1]:= ComplexExpand@Solve [x^2 + x + 1 == 0, x][[#,1,2]]&/@{1,2} Out[1]= {-(1/2) - (I*Sqrt[3])/2, -(1/2) + (I*Sqrt[3])/2} Tomas Garza Mexico City Original Message: ----------------- From: Michaël Monerau mmonerau at gmail.com To: mathgroup at smc.vnet.net Subject: [mg54543] [mg54478] Solutions of an equation under complex form Hello, I'm running into a little problem under Mathematica 5.0 but I'm sure people here will just take it as "too easy", but, well :) I just want the solutions of the equation : x^2 + x + 1 == 0 under their complex form. So, I type : Solve [x^2 + x + 1 == 0, x] But I unfortunately get : { { {x -> -(-1)^(1/3) }, { x -> (-1)^(2/3) } } } And I'd prefer to obtain the more "readable" form : -1/2 + I*1/2*Sqrt[3], -1/2 - I*1/2*Sqrt[3] that I would get under another system for instance. What special function should I call to get this form under Mathematica ? Thanks for any help -- Michaël Monerau -= JJG =- -------------------------------------------------------------------- mail2web - Check your email from the web at http://mail2web.com/ .