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Re: Solutions of an equation under complex form
*To*: mathgroup at smc.vnet.net
*Subject*: [mg54543] Re: [mg54478] Solutions of an equation under complex form
*From*: "tgarza01 at prodigy.net.mx" <tgarza01 at prodigy.net.mx>
*Date*: Tue, 22 Feb 2005 04:24:59 -0500 (EST)
*Reply-to*: tgarza01 at prodigy.net.mx
*Sender*: owner-wri-mathgroup at wolfram.com
Try this:
In[1]:=
ComplexExpand@Solve [x^2 + x + 1 == 0, x][[#,1,2]]&/@{1,2}
Out[1]=
{-(1/2) - (I*Sqrt[3])/2, -(1/2) + (I*Sqrt[3])/2}
Tomas Garza
Mexico City
Original Message:
-----------------
From: Michaël Monerau mmonerau at gmail.com
To: mathgroup at smc.vnet.net
Subject: [mg54543] [mg54478] Solutions of an equation under complex form
Hello,
I'm running into a little problem under Mathematica 5.0 but I'm sure
people here will just take it as "too easy", but, well :) I just want
the solutions of the equation :
x^2 + x + 1 == 0
under their complex form.
So, I type :
Solve [x^2 + x + 1 == 0, x]
But I unfortunately get :
{ { {x -> -(-1)^(1/3) }, { x -> (-1)^(2/3) } } }
And I'd prefer to obtain the more "readable" form :
-1/2 + I*1/2*Sqrt[3], -1/2 - I*1/2*Sqrt[3]
that I would get under another system for instance. What special function
should I call to get this form under Mathematica ?
Thanks for any help
--
Michaël Monerau
-= JJG =-
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