Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2005
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2005

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Simplify and Abs

  • To: mathgroup at smc.vnet.net
  • Subject: [mg54657] Re: Simplify and Abs
  • From: "Dana" <delouis at bellsouth.net>
  • Date: Fri, 25 Feb 2005 01:19:07 -0500 (EST)
  • References: <cvk3fu$d6j$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

With version 5

Refine[Abs[p - 1], 1/2 < p < 1]
1 - p

HTH
-- 
Dana DeLouis


"Simon Anders" <simon.anders at uibk.ac.at> wrote in message 
news:cvk3fu$d6j$1 at smc.vnet.net...
> Hi,
>
> can it really be that this is already beyond Mathematica?
>
>    In :=  FullSimplify[Abs[p - 1], p < 1 && p > 1/2]
>
>    Out := Abs[-1 + p]
>
> How do I make Matheamtica notice, that the assumptions constrain the
> argument of Abs[] to positive values?
>
> Any suggestions how to treat these kinds of problems? Specifically, I
> have a list of products of absolute values of simple polynomials in p
> and I know that p is in the interval [0,1].
>
> I would like to know whether the polynomials have constant sign over the
> interval so that the Abs[] can be removed. Can this be done automatically?
>
> TIA
>   Simon
> 


  • Prev by Date: Re: Saving file problem
  • Next by Date: Re: pattern matching all list elements but last
  • Previous by thread: Re: Simplify and Abs
  • Next by thread: Re: Simplify and Abs