Re: Computing Complex Series Solution using Mathematica

*To*: mathgroup at smc.vnet.net*Subject*: [mg54644] Re: Computing Complex Series Solution using Mathematica*From*: "Jens-Peer Kuska" <kuska at informatik.uni-leipzig.de>*Date*: Fri, 25 Feb 2005 01:18:42 -0500 (EST)*Organization*: Uni Leipzig*References*: <cvhiv9$s5r$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

Hi, can you tell us *what* you plan to do ? Sinh[lambda*x] is no complex series, if you whish to use the series expansion Sinh[y]:> Sum[y^(2n + 1)/(2n + 1)!, {n, 0, Infinity}] you should do that, if you use Sum[] Mathematica will simplify it to Sinh[x], if you whant to keep the series form, you should use the new symbol "sum" instead of Sum in the expression above. Anyway it seems to be better to work with a sum Sinh[] and not with the power series. Regards Jens "Pratik Desai" <pdesai1 at umbc.edu> schrieb im Newsbeitrag news:cvhiv9$s5r$1 at smc.vnet.net... > Hello All, > > I am trying to check the convergence or lack there of a complex series > > Sinh[lamda*x] > > where the first six lamda are given as > lamda={-0.331+3.162*I,-0.435+6.234*I,-0.093+9.418*I,-0.203+12.566*I,-0.365+15.669*I}; > x=Range[0,1,0.1]; > > I want to do more efficiently the following: > > s4=Sinh[lamda[[1]]*x]+Sinh[lamda[[2]]*x]+Sinh[lamda[[3]]*x]+Sinh[lamda[[4]]*x] > > I tried using Sum but to no great success, however I found a neat > mathematica notebook on the function Sinh and I found the following > expansion of sinh > > I was wondering how I could implement the above series in my application > or anyother approach that would be more feasible . > > Thanks > > Pratik Desai >

**Follow-Ups**:**Re: Re: Computing Complex Series Solution using Mathematica***From:*Pratik Desai <pdesai1@umbc.edu>