Re: Form of a linear equation

*To*: mathgroup at smc.vnet.net*Subject*: [mg53761] Re: [mg53734] Form of a linear equation*From*: yehuda ben-shimol <benshimo at bgu.ac.il>*Date*: Wed, 26 Jan 2005 04:37:28 -0500 (EST)*References*: <200501251003.FAA14449@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

s = (-(4 + 4x + y)/17^(1/2) == (2 + x + y)/2^(1/2)) /. Equal[a_, b_] -> a - b; Then use Collect to arrange the coefficients of the variables in the form you need. Collect[s,{x,y}]==0 yehuda DJ Craig wrote: >I'm trying to convert this linear equation: > >-(4+4x+y) / 17^(1/2) = (2+x+y) / 2^(1/2) > >into the form: > >(a_)*x + (b_)*y + (c_) = 0 > >This sounds simple enough, but I can't figure out how to make >Mathematica do it. My TI-89 does it automatically, but I need to be >able to do this like a batch process for a bunch of linear equations. >Heres the solution the TI-89 gives me: > >\!\(\* >StyleBox[\(\((\(\(-4\)\ \@17\)\/17 - \@2\/2)\)\ x + \((\(-\@17\)\/17 >- \ >\@2\/2)\)\ y - \(3\ \@17\)\/17 - \@2 = 0\), >FontWeight->"Bold"]\) > >Just copy and paste that mess into Mathematica and it will change into >the equation at the top, but in the form that I want it. > >I haven't been using Mathematica for long. I'm used to my TI-89; I've >been using it for years. > > >

**References**:**Form of a linear equation***From:*"DJ Craig" <spit@djtricities.com>