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Re: Form of a linear equation


s = (-(4 + 4x + y)/17^(1/2) == (2 + x + y)/2^(1/2)) /. Equal[a_, b_] -> 
a - b;
Then use Collect to arrange the coefficients of the variables in the 
form you need.
Collect[s,{x,y}]==0
yehuda

DJ Craig wrote:

>I'm trying to convert this linear equation:
>
>-(4+4x+y) / 17^(1/2) = (2+x+y) / 2^(1/2)
>
>into the form:
>
>(a_)*x + (b_)*y + (c_) = 0
>
>This sounds simple enough, but I can't figure out how to make
>Mathematica do it.  My TI-89 does it automatically, but I need to be
>able to do this like a batch process for a bunch of linear equations.
>Heres the solution the TI-89 gives me:
>
>\!\(\*
>StyleBox[\(\((\(\(-4\)\ \@17\)\/17 - \@2\/2)\)\ x + \((\(-\@17\)\/17
>- \
>\@2\/2)\)\ y - \(3\ \@17\)\/17 - \@2 = 0\),
>FontWeight->"Bold"]\)
>
>Just copy and paste that mess into Mathematica and it will change into
>the equation at the top, but in the form that I want it.
>
>I haven't been using Mathematica for long.  I'm used to my TI-89; I've
>been using it for years.
>
>  
>


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