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MathGroup Archive 2005

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Re: Re: how to find n in expression x^n using a pattern?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg58505] Re: [mg58487] Re: [mg58426] how to find n in expression x^n using a pattern?
  • From: Andrzej Kozlowski <akoz at mimuw.edu.pl>
  • Date: Tue, 5 Jul 2005 01:57:44 -0400 (EDT)
  • References: <200507020806.EAA01589@smc.vnet.net> <200507040624.CAA05758@smc.vnet.net> <26A87A3E-2A81-483F-B880-FD4E30020592@gmail.com>
  • Sender: owner-wri-mathgroup at wolfram.com

On 4 Jul 2005, at 18:32, Andrzej Kozlowski wrote:
>
> Timing[Cases[p[x], x^(n_.) -> n, {1}]]
>
>
> {0.0005019999999973379*Second, {5}}
>
> (as I wrote in my first response, giving the correct level  
> specification is important).
>

On the other hand, the default level specification for Cases is, of  
course, {1}...

Andrzej Kozlowski


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