Re: Re: how to find n in expression x^n using a pattern?

*To*: mathgroup at smc.vnet.net*Subject*: [mg58505] Re: [mg58487] Re: [mg58426] how to find n in expression x^n using a pattern?*From*: Andrzej Kozlowski <akoz at mimuw.edu.pl>*Date*: Tue, 5 Jul 2005 01:57:44 -0400 (EDT)*References*: <200507020806.EAA01589@smc.vnet.net> <200507040624.CAA05758@smc.vnet.net> <26A87A3E-2A81-483F-B880-FD4E30020592@gmail.com>*Sender*: owner-wri-mathgroup at wolfram.com

On 4 Jul 2005, at 18:32, Andrzej Kozlowski wrote: > > Timing[Cases[p[x], x^(n_.) -> n, {1}]] > > > {0.0005019999999973379*Second, {5}} > > (as I wrote in my first response, giving the correct level > specification is important). > On the other hand, the default level specification for Cases is, of course, {1}... Andrzej Kozlowski

**References**:**how to find n in expression x^n using a pattern?***From:*"steve" <nma124@hotmail.com>

**Re: how to find n in expression x^n using a pattern?***From:*Pratik Desai <pdesai1@umbc.edu>