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Re: Can't assign value to symbols
*To*: mathgroup at smc.vnet.net
*Subject*: [mg58585] Re: [mg58528] Can't assign value to symbols
*From*: Bruce Colletti <vze269bv at verizon.net>
*Date*: Fri, 8 Jul 2005 00:46:18 -0400 (EDT)
*Sender*: owner-wri-mathgroup at wolfram.com
Andrzej
Your reply has led me to the following code, which improves an earlier posting. Your idea to use strings led to doing so for T-row #1.
Other than T[[1]] not being the symbols list {a,b,c}, do you see a problem with the code below?
Bruce
a = b = c = 2;
T = {{"a", "b", "c"}, {3, 4, 2}, {12, 2, 1}, {6, 5, -3}};
Scan[Clear, T[[1]]];
Do[MapThread[Set, {Y = ToExpression@T[[1]], T[[k]]}];
Print[a + b + c, " ", Total@Y];
Scan[Clear, T[[1]]],
{k, 2, Length@T}];
=====================
From: Andrzej Kozlowski <akozlowski at gmail.com>
To: mathgroup at smc.vnet.net
Subject: [mg58585] [mg58528] Re: [mg58513] Re: [mg58458] Re: [mg58444] Re: [mg58409] Can't assign value to symbols
Bruce
The only way I can imagine of dealing with this situation is if you
first make sure that the data that are originally imported into
Mathematica are imported as a string and not an expression. (This is
easy to do with external data with Mathematica functions ReadList or
Import ). So, for example, if to start with T has the form
T = "{{a,b,c},{3,4,2},{12,2,1},{6,5,-3}}";
Then all you need to do is:
Scan[Clear, StringCases[T, LetterCharacter]]
and all the prior values of a, b, and c will b cleared. You can then
convert T to Expression with ToExpression.
Andrzej
On 5 Jul 2005, at 23:35, Bruce Colletti wrote:
> Andrzej
>
> Yes, your idea does work! Thanks.
>
> I've moved your Scan to the inside-end of the loop, since it kills
> two birds with one stone. The code below works as intended unless
> a,b,c have values (and then error messages abound).
>
> The only way I know to avoid this problem is to make Scan
> [Clear,Names["Global`*"]] the new first line...except that this
> (unfortunately) zaps ALL variables.
>
> There must be a better way (than my above idea) to clear the T[[1]]-
> variables (that may have values coming into the code below).
>
> How would you tell Mathematica to hold unevaluated the T[[1]]-
> elements so that they can be used to clear the associated variables?
>
> Bruce
>
> T={{a,b,c},{3,4,2},{12,2,1},{6,5,-3}};
> X=Map[SymbolName,T[[1]]];
>
> Do[Print@MapThread[Set,{ToExpression[X,StandardForm,Unevaluated],T
> [[k]]}];
> Scan[Clear,X],
> {k,2,Length@T}];
>
>
> =====================
> From: Andrzej Kozlowski <akozlowski at gmail.com>
To: mathgroup at smc.vnet.net
> Date: Tue Jul 05 04:38:50 CDT 2005
> To: Bruce Colletti <vze269bv at verizon.net>
> Subject: [mg58585] [mg58528] Re: [mg58513] Re: [mg58458] Re: [mg58444] Re: [mg58409]
> Can't assign value to symbols
>
> I see. In this case, does not
>
> Scan[Clear,X]
>
> after the Do loop do what you want?
>
> Andrzej
>
> On 5 Jul 2005, at 17:31, Bruce Colletti wrote:
>
>
>
>
>> Andrzej
>>
>> The aim is to explictly avoid (throughout the code) referring to
>> the variables.
>>
>> For instance, suppose matrix T (in my code) springs from an Excel
>> spreadsheet imported into Mathematica, one whose top row declares
>> the variable names, and whose later rows give the variables' values
>> for each iteration in a simulation. Suppose further that the
>> number of columns may change.
>>
>> Bruce
>>
>>
>> Bruce
>>
>> =====================
>> From: Andrzej Kozlowski <akozlowski at gmail.com>
To: mathgroup at smc.vnet.net
>> Date: Tue Jul 05 00:57:52 CDT 2005
>> Subject: [mg58585] [mg58528] [mg58513] Re: [mg58458] Re: [mg58444] Re: [mg58409] Can't
>> assign value to symbols
>>
>> To tell the truth, I don't understand what you are trying to do. Why
>> do you want to reevaluate the line X=... ?
>>
>> If you do not want at the end of your Do loop the variables a,b,c to
>> have assigned values the simplest way is to use Block:
>>
>> Block[{a, b, c}, Do[
>> Print@MapThread[Set, {ToExpression[X,
>> StandardForm, Unevaluated], T[[k]]}],
>> {k, 2, Length@T}]];
>>
>> All the assignments will now take place locally inside Block and the
>> variables {a,b,c} are automatically cleared on exit-ting Block.
>>
>> Andrzej Kozlowski
>>
>>
>> On 5 Jul 2005, at 00:18, Bruce Colletti wrote:
>>
>>
>>
>>
>>
>>> Andrzej
>>>
>>> Using your reply, I offer this code for Lee's consideration.
>>>
>>> Although it works when first run, if re-run without quitting the
>>> kernal, the "X= line" causes an error because a,b,c are
>>> instantiated.
>>>
>>> At the start of the program, how can I clear these variables
>>> WITHOUT explicitly declaring them? I've failed to find the right
>>> argument for Clear (e.g., Clear at Subscript...can't find the right
>>> counterpart for Subscript).
>>>
>>> Thankx.
>>>
>>> Bruce
>>>
>>>
>>> T={{a,b,c},{3,4,2},{12,2,1},{6,5,-3}};
>>>
>>> X=Map[SymbolName,T[[1]]];
>>>
>>> Do[Apply[Clear,ToExpression[X,StandardForm,Unevaluated]];
>>> Print@MapThread[Set,{ToExpression[X,StandardForm,Unevaluated],T
>>> [[k]]}],
>>> {k,2,Length@T}];
>>>
>>> =====================
>>> From: Andrzej Kozlowski <akozlowski at gmail.com>
To: mathgroup at smc.vnet.net
>>>
>>>
>>>
>>>
>>> Date: Sun Jul 03 02:57:11 CDT 2005
>>> Subject: [mg58585] [mg58528] [mg58513] [mg58458] Re: [mg58444] Re: [mg58409] Can't
>>> assign value
>>> to symbols
>>>
>>> Instead of ToExpression use
>>>
>>> ToExpression[#, StandardForm, Unevaluated] &
>>>
>>> For example:
>>>
>>>
>>> In[1]:=
>>> parameters = {{"a", "b", "c"}, {1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
>>>
>>> In[2]:=
>>> MapThread[(#1 = #2) & , {ToExpression[#,StandardForm,Unevaluated]
>>> & /@
>>> parameters[[1]],
>>> parameters[[3]]}] ;
>>>
>>> In[3]:=
>>> a
>>>
>>> Out[3]=
>>> 4
>>>
>>> In[4]:=
>>> MapThread[(#1 = #2) & , {ToExpression[#,StandardForm,Unevaluated]
>>> & /@
>>> parameters[[1]],
>>> parameters[[2]]}] ;
>>>
>>> In[5]:=
>>> a
>>>
>>> Out[5]=
>>> 1
>>>
>>>
>>> Of course instead of Standardform you can use TraditionalForm or
>>> even
>>> InputForm.
>>>
>>> Andrzej Kozlowski
>>>
>>> Chiba, Japan
>>>
>>>
>>> On 2 Jul 2005, at 17:07, Lee Newman wrote:
>>>
>>>
>>>
>>>
>>>
>>>
>>>> Thanks for the solutions. I'm running with David Park's solution,
>>>> but
>>>> now realize there is one additional problem. Once I've executed
>>>> the
>>>> statement MapThread[(#1 = #2) & , {parameters[[1]], parameters
>>>> [[3]]}] ,
>>>> because I've specified the first row of "parameters" as symbols,
>>>> this
>>>> row now loses the symbol names and takes on the assigned values,
>>>> such
>>>> that my attempt to execute the MapThread Statement again for a
>>>> different
>>>> set of values, e.g. parameters[[2]], fails.
>>>>
>>>> in: MapThread[(#1 = #2) & , {parameters[[1]], parameters[[3]]}] ;
>>>> in: {a,b,c}
>>>> Out: {4,5,6}
>>>> in: MapThread[(#1 = #2) & , {parameters[[1]], parameters[[2]]}] ;
>>>> out: Set:: setraw : Cannot assign to raw object 4 ... etc
>>>>
>>>> I want to preserve the first row of "parameters" as the symbol
>>>> names, so
>>>> one solution is to use strings, and modify David Park's solution to
>>>> turn
>>>> the strings into symbol names when assigned, This works the first
>>>> time
>>>> it is run, and parameters[[1]] still contains the strings, but ut
>>>> still
>>>> fails the second time. but why?
>>>> in: parameters = {{"a", "b", "c"}, {1, 2, 3}, {4, 5, 6}, {7, 8,
>>>> 9}};
>>>> in: MapThread[(#1 = #2) & , {ToExpression /@ parameters[[1]],
>>>> parameters[[3]]}] ;
>>>> in: {a,b,c}
>>>> out {4,5,6}
>>>> in: MapThread[(#1 = #2) & , {ToExpression /@ parameters[[1]],
>>>> parameters[[3]]}] ;
>>>> out: Set:: setraw : Cannot assign to raw object 4 ... etc
>>>>
>>>> why does the MapThread statement fail the second time? It seems
>>>> ToExpression/@parameters[[1]] converts the strings "a", "b", "c" to
>>>> symbols but then evaluates them prior to returning them, so the
>>>> attempt
>>>> to assign to them in MapThread fails.
>>>>
>>>> How can I modify the MapThread statement so I can call it multiple
>>>> times, each time assigning values to the symbols identified by the
>>>> strings in the first row??
>>>>
>>>> Lee
>>>>
>>>>
>>>>
>>>> David Park wrote:
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>> Lee,
>>>>>
>>>>> Set (=) has a higher precedence Than Function (&). So all you have
>>>>> to do is
>>>>> add parentheses.
>>>>>
>>>>> parameters = {{a, b, c}, {1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
>>>>>
>>>>> MapThread[(#1 = #2) & , {parameters[[1]], parameters[[3]]}]
>>>>> {4, 5, 6}
>>>>>
>>>>> David Park
>>>>> djmp at earthlink.net
>>>>> http://home.earthlink.net/~djmp/
>>>>>
>>>>> From: Lee Newman [mailto:leenewm at umich.edu]
To: mathgroup at smc.vnet.net
>>>>>
>>>>>
>>>>>
>>>>>
>>>>>
>>>>>
>>>>>
>>>>> Hello,
>>>>>
>>>>> Situation: I have a table that contains parameters and sets of
>>>>> values
>>>>> that I want to assign to the parameters for the purposes of
>>>>> running a
>>>>> simulation.
>>>>> - parameters = {{a,b,c},{1,2,3},{4,5,6},{7,8,9}}
>>>>> - want to assign values in a given row to the symbols listed in
>>>>> the
>>>>> first row.
>>>>> - tried using: MapThread[ #1 = #2 &, {parameters[[1]],
>>>>> parameters
>>>>> [[3]]} ]
>>>>> - fails with error "Tag Slot in #1 is Protected"
>>>>> - tried adding Unprotect[#1] and a variety of other attemps, but
>>>>> can't
>>>>> get it to work.
>>>>>
>>>>> Anyone know how might accomplish this?
>>>>>
>>>>> Thanks,
>>>>> Lee
>>>>>
>>>>>
>>>>>
>>>>>
>>>>>
>>>>>
>>>>>
>>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>
>>
>>
>>
>>
>
>
>
>
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