Re: evaluate assuming odd integers?

*To*: mathgroup at smc.vnet.net*Subject*: [mg58982] Re: [mg58961] evaluate assuming odd integers?*From*: Bob Hanlon <hanlonr at cox.net>*Date*: Tue, 26 Jul 2005 04:01:47 -0400 (EDT)*Reply-to*: hanlonr at cox.net*Sender*: owner-wri-mathgroup at wolfram.com

Clear[n]; int=Integrate[Sin[n*Pi*(z/L)],{z,0,L}]; Simplify[ Simplify[ int/.n->2*m+1, Element[m, Integers]]/. m->(n-1)/2] (2*L)/(n*Pi) Bob Hanlon > > From: "ab at sd.com" <at2 at ads.com> To: mathgroup at smc.vnet.net > Date: 2005/07/25 Mon AM 01:12:15 EDT > Subject: [mg58982] [mg58961] evaluate assuming odd integers? > > Is there a way in Mathematica to evaluate an expression assuming some > varialbe is Odd integer, for example in below integral how can i tell it > that n is odd integer in the Assumptions section of FullSimplify command or > the integral itself??: > In[35]:= > Integrate[Sin[n*Pi*(z/L)], {z, 0, L}] > FullSimplify[%, n \[Element] Integers && n >= 0 && > L \[Element] Reals && L > 0 && z \[Element] Reals] > >