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Re: evaluate assuming odd integers?
*To*: mathgroup at smc.vnet.net
*Subject*: [mg58982] Re: [mg58961] evaluate assuming odd integers?
*From*: Bob Hanlon <hanlonr at cox.net>
*Date*: Tue, 26 Jul 2005 04:01:47 -0400 (EDT)
*Reply-to*: hanlonr at cox.net
*Sender*: owner-wri-mathgroup at wolfram.com
Clear[n];
int=Integrate[Sin[n*Pi*(z/L)],{z,0,L}];
Simplify[
Simplify[
int/.n->2*m+1,
Element[m, Integers]]/.
m->(n-1)/2]
(2*L)/(n*Pi)
Bob Hanlon
>
> From: "ab at sd.com" <at2 at ads.com>
To: mathgroup at smc.vnet.net
> Date: 2005/07/25 Mon AM 01:12:15 EDT
> Subject: [mg58982] [mg58961] evaluate assuming odd integers?
>
> Is there a way in Mathematica to evaluate an expression assuming some
> varialbe is Odd integer, for example in below integral how can i tell it
> that n is odd integer in the Assumptions section of FullSimplify command
or
> the integral itself??:
> In[35]:=
> Integrate[Sin[n*Pi*(z/L)], {z, 0, L}]
> FullSimplify[%, n \[Element] Integers && n >= 0 &&
> L \[Element] Reals && L > 0 && z \[Element] Reals]
>
>
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