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Re: evaluate assuming odd integers?
*To*: mathgroup at smc.vnet.net
*Subject*: [mg58991] Re: [mg58961] evaluate assuming odd integers?
*From*: Pratik Desai <pdesai1 at umbc.edu>
*Date*: Tue, 26 Jul 2005 04:02:01 -0400 (EDT)
*References*: <200507250512.BAA04841@smc.vnet.net>
*Sender*: owner-wri-mathgroup at wolfram.com
ab at sd.com wrote:
>Is there a way in Mathematica to evaluate an expression assuming some
>varialbe is Odd integer, for example in below integral how can i tell it
>that n is odd integer in the Assumptions section of FullSimplify command or
>the integral itself??:
>In[35]:=
>Integrate[Sin[n*Pi*(z/L)], {z, 0, L}]
>FullSimplify[%, n \[Element] Integers && n >= 0 &&
>L \[Element] Reals && L > 0 && z \[Element] Reals]
>
>
>
I guess the two simplest approaches that come to mind are
int[n_?OddQ] = Integrate[Sin[n*Pi*(z/L)], {z, 0, L}]
int2 = Table[Integrate[Sin[(2*n - 1)*Pi*(z/L)], {z, 0, L}], {n, 1, 5}]
Best regards
Pratik
--
Pratik Desai
Graduate Student
UMBC
Department of Mechanical Engineering
Phone: 410 455 8134
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