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Re: Simplification question

  • To: mathgroup at
  • Subject: [mg59057] Re: [mg59032] Simplification question
  • From: Curtis Osterhoudt <gardyloo at>
  • Date: Thu, 28 Jul 2005 02:26:01 -0400 (EDT)
  • Sender: owner-wri-mathgroup at

My only guess is that Cos can return either a positive or negative 1
depending on the integer. It might be nice if Mathematica could return a
piecewise answer depending on what m was, but ...

snoofly wrote:

>Can someone explain this to me please.
>Simplify[Sin[3 m Pi], Assumptions -> m \[Element] Integers]
>Simplify[Cos[3 m Pi], Assumptions -> m \[Element] Integers]
>Cos[3 m \[Pi]]
>I'm not sure why Mathematica cannot deduce that the second simplification 
>should be (1)^m.

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