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Re: Simplification question


My only guess is that Cos can return either a positive or negative 1
depending on the integer. It might be nice if Mathematica could return a
piecewise answer depending on what m was, but ...

snoofly wrote:

>Can someone explain this to me please.
>
>Clear[m]
>
>Simplify[Sin[3 m Pi], Assumptions -> m \[Element] Integers]
>0
>
>Simplify[Cos[3 m Pi], Assumptions -> m \[Element] Integers]
>
>Cos[3 m \[Pi]]
>
>I'm not sure why Mathematica cannot deduce that the second simplification 
>should be (1)^m.
>
>
>  
>



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