Re: Simplification question

*To*: mathgroup at smc.vnet.net*Subject*: [mg59057] Re: [mg59032] Simplification question*From*: Curtis Osterhoudt <gardyloo at mail.wsu.edu>*Date*: Thu, 28 Jul 2005 02:26:01 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

My only guess is that Cos can return either a positive or negative 1 depending on the integer. It might be nice if Mathematica could return a piecewise answer depending on what m was, but ... snoofly wrote: >Can someone explain this to me please. > >Clear[m] > >Simplify[Sin[3 m Pi], Assumptions -> m \[Element] Integers] >0 > >Simplify[Cos[3 m Pi], Assumptions -> m \[Element] Integers] > >Cos[3 m \[Pi]] > >I'm not sure why Mathematica cannot deduce that the second simplification >should be (1)^m. > > > > -- PGP Key ID: 0x235FDED1 Please avoid sending me Word or PowerPoint attachments. http://www.gnu.org/philosophy/no-word-attachments.html

**Follow-Ups**:**Re: Re: Simplification question***From:*Murray Eisenberg <murray@math.umass.edu>