Re: Simplification question
- To: mathgroup at smc.vnet.net
- Subject: [mg59057] Re: [mg59032] Simplification question
- From: Curtis Osterhoudt <gardyloo at mail.wsu.edu>
- Date: Thu, 28 Jul 2005 02:26:01 -0400 (EDT)
- Sender: owner-wri-mathgroup at wolfram.com
My only guess is that Cos can return either a positive or negative 1 depending on the integer. It might be nice if Mathematica could return a piecewise answer depending on what m was, but ... snoofly wrote: >Can someone explain this to me please. > >Clear[m] > >Simplify[Sin[3 m Pi], Assumptions -> m \[Element] Integers] >0 > >Simplify[Cos[3 m Pi], Assumptions -> m \[Element] Integers] > >Cos[3 m \[Pi]] > >I'm not sure why Mathematica cannot deduce that the second simplification >should be (1)^m. > > > > -- PGP Key ID: 0x235FDED1 Please avoid sending me Word or PowerPoint attachments. http://www.gnu.org/philosophy/no-word-attachments.html
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