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Re: Re: Limit of list

  • To: mathgroup at smc.vnet.net
  • Subject: [mg57596] Re: [mg57527] Re: Limit of list
  • From: Paul Abbott <paul at physics.uwa.edu.au>
  • Date: Wed, 1 Jun 2005 06:04:34 -0400 (EDT)
  • References: <d79ejm$lb1$1@smc.vnet.net> <200505310859.EAA03396@smc.vnet.net> <opsrnpltapiz9bcq@monster.ma.dl.cox.net>
  • Sender: owner-wri-mathgroup at wolfram.com

>SequenceLimit. Another COMPLETELY undocumented feature.

Not COMPLETELY undocumented. Try

   ?SequenceLimit

>Just as well, I guess, since it can't possibly work.

Why not? SequenceLimit returns the approximation given by Wynn's 
epsilon algorithm to the limit of a sequence whose first few terms 
are given by list. This algorithm can give finite results for 
divergent sequences. As I understand it, SequenceLimit is used by 
NIntegrate when Method->Oscillatory.

Cheers,
Paul


>
>Bobby
>
>On Tue, 31 May 2005 04:59:40 -0400 (EDT), Paul Abbott 
><paul at physics.uwa.edu.au> wrote:
>
>>In article <d79ejm$lb1$1 at smc.vnet.net>,
>>  Guy Israeli <guyi1 at netvision.net.il> wrote:
>>
>>>Is there a way to find out the convergence point of a list of numbers?
>>>
>>>for example if I have
>>>
>>>{1,2,5,6,8,9,10,11,10,11,12,11,12.. and so on}
>>>
>>>it will give me something around 10-12
>>
>>Try SequenceLimit:
>>
>>   SequenceLimit[{1,2,5,6,8,9,10,11,10,11,12,11,12}]
>>
>>Also, if your list is entering a cycle there have been previous
>>MathGroup postings on methods for detecting cycles.
>>
>>Cheers,
>>Paul
>>
>
>
>
>--
>DrBob at bigfoot.com



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