Re: simple set operations

*To*: mathgroup at smc.vnet.net*Subject*: [mg57646] Re: simple set operations*From*: Felix Kossak <felix.kossak at scch.at>*Date*: Fri, 3 Jun 2005 05:33:27 -0400 (EDT)*References*: <d7mk8b$c5m$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

Hi, (1) I guess CharacterRange[ "a", "h" ] will do what you want. (2) should be solved by MemberQ, i.e. If[ MemberQ[ mylist, "a" ], Print[ ... ] ]; Best, Felix Edward Peschko wrote: > hey all, > > I'm hesitant to ask these questions (because they are so simple) but after a > 15 minute search through the docs I'm getting nowhere, so here goes: > > 1) what's the easiest way to generate a list of elements? ie: > > 'a' .. 'h' == { a,b,c,d,e,f,g,h } > > 2) Is there a quick way to check whether an element is in a set? > > if ('a' == (any('a','b','c','d')) { print "a is in a,b,c,d"; } > > The first one I see could possibly be done by 'Array', but I don't see how - > the '#' refers to the generation of numbers, but there seems to be no > corresponding 'letter' symbol. > > > As for #2, the easiest way would be through an overloading of the '==' operator, > but again, that doesn't seem to work.. > > Thanks much for any help, > > Ed >