Re: simple set operations

• To: mathgroup at smc.vnet.net
• Subject: [mg57646] Re: simple set operations
• From: Felix Kossak <felix.kossak at scch.at>
• Date: Fri, 3 Jun 2005 05:33:27 -0400 (EDT)
• References: <d7mk8b\$c5m\$1@smc.vnet.net>
• Sender: owner-wri-mathgroup at wolfram.com

```Hi,

(1) I guess CharacterRange[ "a", "h" ] will do what you want.

(2) should be solved by MemberQ, i.e.

If[ MemberQ[ mylist, "a" ], Print[ ... ] ];

Best,
Felix

Edward Peschko wrote:
> hey all,
>
> I'm hesitant to ask these questions (because they are so simple) but after a
> 15 minute search through the docs I'm getting nowhere, so here goes:
>
>     1) what's the easiest way to generate a list of elements? ie:
>
> 	'a' .. 'h' == { a,b,c,d,e,f,g,h }
>
>     2) Is there a quick way to check whether an element is in a set?
>
> 	if ('a' == (any('a','b','c','d')) { print "a is in a,b,c,d"; }
>
> The first one I see could possibly be done by 'Array', but I don't see how -
> the '#' refers to the generation of numbers, but there seems to be no
> corresponding 'letter' symbol.
>
>
> As for #2, the easiest way would be through an overloading of the '==' operator,
> but again, that doesn't seem to work..
>
> Thanks much for any help,
>
> Ed
>

```

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