Re: simple set operations

*To*: mathgroup at smc.vnet.net*Subject*: [mg57655] Re: simple set operations*From*: dh <dh at metrohm.ch>*Date*: Fri, 3 Jun 2005 05:33:39 -0400 (EDT)*References*: <d7mk8b$c5m$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

Hi Ed, see below. Sincerely, Daniel Edward Peschko wrote: > hey all, > > I'm hesitant to ask these questions (because they are so simple) but after a > 15 minute search through the docs I'm getting nowhere, so here goes: > > 1) what's the easiest way to generate a list of elements? ie: > > 'a' .. 'h' == { a,b,c,d,e,f,g,h } I would numerate the elements. It is easier to work with numbers than with characters. If you want to see the names, you can put the names in a list or function "names" and get the name by names[[i]] or names[i]. To get the list with numbers: Range[n] > > 2) Is there a quick way to check whether an element is in a set? > > if ('a' == (any('a','b','c','d')) { print "a is in a,b,c,d"; } MemeberQ will help: MemeberQ[List_of_Elements, Element ] > > The first one I see could possibly be done by 'Array', but I don't see how - > the '#' refers to the generation of numbers, but there seems to be no > corresponding 'letter' symbol. > > > As for #2, the easiest way would be through an overloading of the '==' operator, > but again, that doesn't seem to work.. > > Thanks much for any help, > > Ed >