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Function Fit to 3D data set
*To*: mathgroup at smc.vnet.net
*Subject*: [mg57748] Function Fit to 3D data set
*From*: Adrienne R <roehrich at unlserve.unl.edu>
*Date*: Tue, 7 Jun 2005 02:03:52 -0400 (EDT)
*Sender*: owner-wri-mathgroup at wolfram.com
I have been trying to do several analyses with an [x,y,z] data set, where z is dependent on x and y. First, I tried a 3D plot. However, the only way I was able to get Mathematica to plot my data was to assume a grid form for x and y, and use ListPlot3D. First question: can Mathematica make a 3D plot from stated x,y,z points?
Secondly, I am trying to fit a function to the data. I have determined a function to which to fit parameters. However, Mathematica does not seem to want to accept y as a variable. Here is a simple suggestion of what I was trying. Note, my function is much more complicated. Please also ignore if the given does not work as stated, as I'm making it up.
points = {{1, 1, 1}, {1, 2, 4}, {1, 4, 16}}
f1 = FindFit[points, a + b*x^0 * y^1 + c*x^0 *y^2 +k*x^2 *y^0 + l*x^2 * y^1, {a, b, c, k, l}, x, y]
The error I receive is \!\(\*
RowBox[{\(FindFit::"nonopt
"\), \(\(:\)\(\ \)\), "\<\"Options expected (
instead of \\!\\(y\\)) beyond
position \\!\\(4\\) in \\!\\(\[LeftSkeleton] 1 \[RightSkeleton]\\). An \
option must be a rule or a list of rules. \\!\\(\\*ButtonBox[\\\"Moreâ?¦\\\", \
ButtonStyle->\\\"RefGuideLinkText\\\", ButtonFrame->None, \
ButtonData:>\\\"General::nonopt\\\"]\\)\"\>"}]\)
Second question: Can Mathematica take a set of x,y,z data where z is dependent on x and y and fit a function to it?
Secondary question for both: How?
Thanks for the help!
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