Re: Mathematica equivalent complexplot

*To*: mathgroup at smc.vnet.net*Subject*: [mg57845] Re: Mathematica equivalent complexplot*From*: "David Park" <djmp at earthlink.net>*Date*: Fri, 10 Jun 2005 02:29:09 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

Ron, I think you are attempting to plot a curve in the complex plane. You can do it as follows. Needs["Graphics`Colors`"] f[x_] = Sin[x + I] I*Sinh[1 - I*x] (Mathematica automatically transformed the Sin expression.) ParametricPlot[{Re[f[x]], Im[f[x]]}, {x, -Pi, Pi}, AspectRatio -> Automatic, PlotLabel -> SequenceForm["Curve ", f[x], " in Complex Plane"], Frame -> True, FrameLabel -> {"Re", "Im"}, FrameTicks -> Automatic, Background -> Linen, ImageSize -> 400]; For those who have the complex graphics package, Cardano3, from my web site below, there is a ComplexCurve routine (suggested by Murray Eisenberg). Cardano3 also requires DrawGraphics. Then the plot is done with... Needs["Cardano3`ComplexGraphics`"] ComplexGraphics[ {ComplexCurve[f[x], {x, -Pi, Pi}]}, PlotLabel -> SequenceForm["Curve ", f[x], " in Complex Plane"], FrameLabel -> {"Re", "Im"}, FrameTicks -> Automatic, Background -> Linen]; David Park djmp at earthlink.net http://home.earthlink.net/~djmp/ From: raf . [mailto:arawak1 at yahoo.com] To: mathgroup at smc.vnet.net This is a newbie question, I suppose. I've read as much as I can but cannot find a straight forward way to implement the complexplot in Mathematica 5. An example call could be complexplot(sin(x+i),x=-Pi..Pi) where sin(x+i) is a typical function f(x) that maps real to complex and -Pi..Pi is the domain of f, a..b. Of course, there are various plot options which can follow and would be included before the closing paren but I think I can handle that. So any help would be appreciated. Thanks much for the response. Ron Francis

**Follow-Ups**:**Re: Re: Mathematica equivalent complexplot***From:*Murray Eisenberg <murray@math.umass.edu>