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MathGroup Archive 2005

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Re: How to rotate a PolarPlot?

  • To: mathgroup at
  • Subject: [mg58019] Re: [mg57982] How to rotate a PolarPlot?
  • From: yehuda ben-shimol <bsyehuda at>
  • Date: Thu, 16 Jun 2005 05:36:58 -0400 (EDT)
  • References: <>
  • Reply-to: yehuda ben-shimol <bsyehuda at>
  • Sender: owner-wri-mathgroup at

The iterator of Polar plot determines the angle while the function
determines the radius.
So if you want to "shift" in angle, all you need is to start the angle
from a different initial value , i.e.
PolarPlot[Exp[0.2 (t-t0)],{t,t0,t1}]  where t0 is the initial value,
and t1 is the final value for the angles. Note that t-t0 makes your
function to compute the values for 0<=t<=t2-t1 (which I assume that
you wanted this behavior)

On 6/15/05, paul at <paul at> wrote:
> Hi All,
> Would appreciate some help with this. I would like to know how I can
> rotate the following plot to an arbitrary angle:
> PolarPlot[Exp[.2t], {t, 0, 8p}, PlotStyle -> Red,
>   PlotRange -> All, AspectRatio -> Automatic, Ticks -> None]
> Thanks
> Paul

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