Re: How to rotate a PolarPlot?

• To: mathgroup at smc.vnet.net
• Subject: [mg58019] Re: [mg57982] How to rotate a PolarPlot?
• From: yehuda ben-shimol <bsyehuda at gmail.com>
• Date: Thu, 16 Jun 2005 05:36:58 -0400 (EDT)
• References: <200506150958.FAA29769@smc.vnet.net>
• Reply-to: yehuda ben-shimol <bsyehuda at gmail.com>
• Sender: owner-wri-mathgroup at wolfram.com

```Hi,
The iterator of Polar plot determines the angle while the function
So if you want to "shift" in angle, all you need is to start the angle
from a different initial value , i.e.
PolarPlot[Exp[0.2 (t-t0)],{t,t0,t1}]  where t0 is the initial value,
and t1 is the final value for the angles. Note that t-t0 makes your
function to compute the values for 0<=t<=t2-t1 (which I assume that
you wanted this behavior)
yehuda

On 6/15/05, paul at selfreferral.com <paul at selfreferral.com> wrote:
> Hi All,
>
> Would appreciate some help with this. I would like to know how I can
> rotate the following plot to an arbitrary angle:
>
> PolarPlot[Exp[.2t], {t, 0, 8p}, PlotStyle -> Red,
>   PlotRange -> All, AspectRatio -> Automatic, Ticks -> None]
>
> Thanks
> Paul
>
>

```

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