Re: Solve with assumptions

*To*: mathgroup at smc.vnet.net*Subject*: [mg58284] Re: Solve with assumptions*From*: Bill Rowe <readnewsciv at earthlink.net>*Date*: Sun, 26 Jun 2005 01:33:47 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

On 6/25/05 at 1:56 AM, mbekkali at gmail.com (Mukhtar Bekkali) wrote: >How do you pull the solution out from Reduce? That is, with Solve I >can have x=x/.Solve[f[x]==0,x] and get x and use it later on. The >output of Reduce is identity, x==number. Keep in mind x==number is an expression which can be manipulated with other Mathematica functions. Specifically, note FullForm[Reduce[x + 1 == 0, x]] results in Equal[x, -1] So, the -1 can be extracted using Apply as follows: Last[List@@Reduce[x + 1, x]] or even more directly with Part as Reduce[x + 1 == 0, x][[2]] or Part[Reduce[x +1 == 0, x], 2] -- To reply via email subtract one hundred and four