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Re: findfit or solve?
*To*: mathgroup at smc.vnet.net
*Subject*: [mg55026] Re: findfit or solve?
*From*: "adamizer" <adam.smith at hillsdale.edu>
*Date*: Thu, 10 Mar 2005 05:24:25 -0500 (EST)
*References*: <d0modp$76l$1@smc.vnet.net>
*Sender*: owner-wri-mathgroup at wolfram.com
For this to work in Mathematica you need to fix some syntax problems
and load a special package, Statistic`NonlinearFit`. Be careful, the
symbol enclosing the Nonlinear fit is not a single quote or apostrophe
but a backwards single quote. On my keyboard it is the shifted key to
the left of the "1" key. I have shown the two differenct versions:
NonlinearFit just returns the best fit function. NonlinearRegress
provides more detailed information. See the Help for more info.
In my example below I load the graphics package Graphics`Colors` so
that I can access the color names in the final plot (See the Help under
Colors). I also load Graphics`Graphics` so that I can use the
DisplayTogether command for showing multiple plot.
The code is at the end
Adam Smith
In[1]:=
<< Statistics`NonlinearFit`
In[2]:=
<<Graphics`Graphics`
<<Graphics`Colors`
In[4]:=
func = a - 2*(a-b)/(Exp[c*(t-d)]+Exp[e*(t-d)])
In[5]:=
data={{6.968,117.1},{7.967,123.3},{9.046,129.4},{9.982,134.6},{10.951,
139.2},{11.973,145.2},{13.021,151.1},{13.892,159.9},{14.888,
167.8},{15.858,171.9},{16.857,175.7},{17.854,177.2},{18.724,175.6}};
In[6]:=
fitfunc =
NonlinearFit[data,func,t,{{a,176},{b,160},{c,0.1},{d,14},{e,1.2}}]
In[7]:=
NonlinearRegress[data,func,t,{{a,176},{b,160},{c,0.1},{d,14},{e,1.2}}]
In[9]:=
DisplayTogether[
ListPlot[data],
Plot[func/.{a->176,b->160,c->0.1,d->14,e->1.2},{t,7,20},
PlotStyle\[Rule]{Blue}],
Plot[fitfunc,{t,7,20},PlotStyle\[Rule]{Red}]]
Tegla Bela wrote:
> Greetings to everybody,
>
> I have found a model and I would like to use Mathematica for the data
under
> the model. The model is as follows:
>
> = h1 - ((2 * (h1 - h$B&H(B)) / ((EXP(s0 * (t -$B&H(B))) + (EXP(s1 * (t
-$B&H(B)))))
>
> data = {{6.968, 117.1}, {7.967, 123.3}, {9.046,
> 129.4}, {9.982, 134.6}, {10.951,
> 139.2}, {11.973, 145.2}, {13.021, 151.1}, {13.892, 159.9}, {
> 14.888, 167.8}, {15.858, 171.9}, {16.857, 175.7}, {17.854,
177.2}, {
> 18.724, 175.6}};
>
> I have managed to do it with nonlinear least-square fitting in other
> program. But not working for me in Mathematica. (I do not know how to
give
> initial values to have the five unknown parameters estimated) These
are the
> initial values that I would like to use: a=176, b=160, c=0.1, d=14,
e=1.2
> (t is the age, first value in each pair of the data)
>
> Does anybody have idea how it can be done? Any help is appreciated.
>
> Spiller
>
> _________________________________________________________________
> $BF|K\9qFb:GBg5i(B570$BK|%f!<%6!<$N(BMSN Hotmail
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