Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2005
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2005

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: a simplification problem

  • To: mathgroup at smc.vnet.net
  • Subject: [mg55257] Re: a simplification problem
  • From: Bill Rowe <readnewsciv at earthlink.net>
  • Date: Thu, 17 Mar 2005 03:30:56 -0500 (EST)
  • Sender: owner-wri-mathgroup at wolfram.com

On 3/16/05 at 5:35 AM, fangh73 at xmu.edu.cn (Hui Fang) wrote:

>My questions is simple: How do I simplify (-1)^(1/3) to -1?

On one level the answer is you don't since

{(-1)^3,(1/2 + I Sqrt[3]/2)^3,(1/2 - I Sqrt[3]/2)^3}//Simplify

gives

{-1, -1, -1}

But if you want to force Mathematica to get a real cube root of a negative number, load the package Miscellaneous`RealOnly`
--
To reply via email subtract one hundred and four


  • Prev by Date: Re: bug in series expansion routines.
  • Next by Date: Re: Combination
  • Previous by thread: Re: a simplification problem
  • Next by thread: Re: a simplification problem