Re: a simplification problem
- To: mathgroup at smc.vnet.net
- Subject: [mg55234] Re: [mg55172] a simplification problem
- From: DrBob <drbob at bigfoot.com>
- Date: Thu, 17 Mar 2005 03:29:20 -0500 (EST)
- References: <200503161035.FAA23728@smc.vnet.net>
- Reply-to: drbob at bigfoot.com
- Sender: owner-wri-mathgroup at wolfram.com
That's not a simplification; it's the wrong answer. Here's the right one (based on the commonly used "branch" of the exponential): ComplexExpand[(-1)^(1/3)] 1/2 + (I*Sqrt[3])/2 If you mean, "How do I extract the real third root of -1?", here's a method: ComplexExpand[x /. Solve[x^3 == -1]] {-1, 1/2 + (I*Sqrt[3])/2, 1/2 - (I*Sqrt[3])/2} First@Select[%, FreeQ[#1, Complex] & ] -1 Bobby On Wed, 16 Mar 2005 05:35:49 -0500 (EST), Hui Fang <fangh73 at xmu.edu.cn> wrote: > Dear All, > > My questions is simple: > How do I simplify (-1)^(1/3) to -1? > > Thanks! > > > > -- DrBob at bigfoot.com
- References:
- a simplification problem
- From: Hui Fang <fangh73@xmu.edu.cn>
- a simplification problem