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Re: Normal Disappear Problem


gouqizi.lvcha at gmail.com wrote:
> Hi, All:
> 
> I have the following parametric equation for an unit sphere:
> 
> x = cos(u)sin(v)
> y = sin(u)sin(v)
> z = cos(v)
> 
> 0<=u<2*Pi ; 0<=v<=Pi
> 
> Then I use
> 
> normal = (Dx/Du, Dy/Du, Dz/Du) CROSS (Dx/Dv, Dy/Dv, Dz/Dv) to get the
> normal vector.
> 
> I get the follwoing after calculation (with normalization):
> 
> normal =  [sin(v) ^2 cos(u), sin(v)^2  sin(u), cos(u)^2  cos(v) sin(v)
> +  sin(u)^2  cos(v) sin(v)]
> 
> Now when u=0, v=0 , Normal = (0,0,0)! How can it be? We know the fact
> that a sphere should have normal everywhere.
> 
> Rick

http://mathworld.wolfram.com/HairyBallTheorem.html

Your tangent vectors are:

In[2]:= {x,y,z} = {Cos[u]*Sin[v], Sin[u]*Sin[v], Cos[v]};

In[3]:= tanvex = {{D[x,u],D[y,u],D[z,u]},{D[x,v],D[y,v],D[z,v]}}
Out[3]= {{-(Sin[u] Sin[v]), Cos[u] Sin[v], 0},
  {Cos[u] Cos[v], Cos[v] Sin[u], -Sin[v]}}

The theorem indicates each must vanish somewhere, hence their cross 
product must vanish.

Upshot: the sphere has everywhere a unit normal, but it cannot be 
obtained as a cross product from an everywhere smooth tangential frame.


Daniel Lichtblau
Wolfram Research



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