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Re: Controlled evaluation of functions


Clear[f, k]
k[x_]:=x^2
f[1,x_]:=HoldForm@k[x]
f[i_,x_]:=HoldForm@k[i x]
g[x_]=Table[f[i,x],{i,3}]

{k[x],k[2 x],k[3 x]}

{3,0,1}.g[y]
ReleaseHold@%

3 k[y]+k[3 y]
12*y^2

Bobby

On Thu, 5 May 2005 06:02:34 -0400 (EDT), Brett Patterson <muckle.moose at gmail.com> wrote:

> Consider the following behaviour:
>
>   In[1]:= f[i_, x_] := Sin[i x]
>
>   In[2]:= g[x_] = Table[f[i, x], {i, 3}]
>
>   Out[2]= {Sin[x], Sin[2 x], Sin[3 x]}
>
>   In[3]:= {3, 0, 1} . g[y]
>
>   Out[3]= 3 Sin[y] + Sin[3 y]
>
> This is what I want to do, but using my own function instead of Sin.
> However, this is the result:
>
>   In[4]:= k[x_] := x^2           (* This is my alternative to Sin *)
>
>   In[5]:= f[i_, x_] := k[i x]
>
>   In[6]:= g[x_] = Table[f[i, x], {i, 3}]
>
>   Out[6]= {x^2, 4 x^2, 9 x^2}    (* I want {k[x], k[2 x], k[3 x]} *)
>
>   In[7]:= {3, 0, 1} . g[y]
>
>   Out[7]= 12 y^2                 (* I want 3 k[y] + k[3 y] *)
>
> How can I get the function k to behave like Sin, so that it is not
> evaluated?
>
> Note that in my real application, k is a lot more complex and has
> conditions on its arguments, etc.
>
> Thanks!
>
> Brett Patterson
>
>
>
>



-- 
DrBob at bigfoot.com


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