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MathGroup Archive 2005

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Re: GramSchmidt problem

  • To: mathgroup at smc.vnet.net
  • Subject: [mg57043] Re: [mg57023] GramSchmidt problem
  • From: DrBob <drbob at bigfoot.com>
  • Date: Thu, 12 May 2005 22:44:26 -0400 (EDT)
  • References: <200505120634.CAA09007@smc.vnet.net>
  • Reply-to: drbob at bigfoot.com
  • Sender: owner-wri-mathgroup at wolfram.com

The kernel runs out of memory at my machine (Mathematica 5.1.1, WinXP).

Bobby

On Thu, 12 May 2005 02:34:15 -0400 (EDT), Heath Gerhardt <heathgerhardt at hotmail.com> wrote:

> Does anyone know if there are any know problems with GramSchmidt
> crashing Mathematica? When I run it on these 4 25-dimensional vectors it
> crashes on my system:
>
> \!\({1\/2\ \((3 + \@5)\), 1\/2\ \((\(-3\) - \@5)\), 1\/2\ \((1 + \@5)\), 0,
>     1\/2\ \((\(-1\) - \@5)\), 1\/2\ \((\(-3\) - \@5)\), 1\/2\ \((3 + \@5)\),
>     1\/2\ \((\(-1\) - \@5)\), 0, 1\/2\ \((1 + \@5)\), 1\/2\ \((1 + \@5)\),
>     1\/2\ \((\(-1\) - \@5)\), 1, 0, \(-1\), 0, 0, 0, 0, 0,
>     1\/2\ \((\(-1\) - \@5)\), 1\/2\ \((1 + \@5)\), \(-1\), 0, 1}\)
>
> \!\({1\/2\ \((1 + \@5)\), 1\/2\ \((\(-3\) - \@5)\), 1\/2\ \((3 + \@5)\),
>     1\/2\ \((\(-1\) - \@5)\), 0, 1\/2\ \((\(-1\) - \@5)\),
>     1\/2\ \((3 + \@5)\), 1\/2\ \((\(-3\) - \@5)\), 1\/2\ \((1 + \@5)\), 0,
> 1,
>     1\/2\ \((\(-1\) - \@5)\), 1\/2\ \((1 + \@5)\), \(-1\), 0, 0, 0, 0, 0,
>     0, \(-1\), 1\/2\ \((1 + \@5)\), 1\/2\ \((\(-1\) - \@5)\), 1, 0}\)
>
> \!\({1\/2\ \((1 + \@5)\), 1\/2\ \((\(-1\) - \@5)\), 1, 0, \(-1\),
>     1\/2\ \((\(-3\) - \@5)\), 1\/2\ \((3 + \@5)\), 1\/2\ \((\(-1\) - \@5)\),
>     0, 1\/2\ \((1 + \@5)\), 1\/2\ \((3 + \@5)\), 1\/2\ \((\(-3\) - \@5)\),
>     1\/2\ \((1 + \@5)\), 0, 1\/2\ \((\(-1\) - \@5)\),
>     1\/2\ \((\(-1\) - \@5)\), 1\/2\ \((1 + \@5)\), \(-1\), 0, 1, 0, 0, 0, 0,
>     0}\)
>
> \!\({1, 1\/2\ \((\(-1\) - \@5)\), 1\/2\ \((1 + \@5)\), \(-1\), 0,
>     1\/2\ \((\(-1\) - \@5)\), 1\/2\ \((3 + \@5)\), 1\/2\ \((\(-3\) - \@5)\),
>     1\/2\ \((1 + \@5)\), 0, 1\/2\ \((1 + \@5)\), 1\/2\ \((\(-3\) - \@5)\),
>     1\/2\ \((3 + \@5)\), 1\/2\ \((\(-1\) - \@5)\), 0, \(-1\),
>     1\/2\ \((1 + \@5)\), 1\/2\ \((\(-1\) - \@5)\), 1, 0, 0, 0, 0, 0, 0}\)
>
>
> thanks in advance
> Heath
>
>
>
>



-- 
DrBob at bigfoot.com


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