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Re: Re: Crossing of 3D functions
That's not InputForm; this is:
F1 = -7.516*Exp[-3.076*
(r - 1.184)]*
(1 - (8.28*(180 - f)^2)/
10^5)*1^0.5 +
3.758*Exp[-6.152*
(r - 1.184)] + 3.92
F2 = -0.958*Exp[-4.993*
(r - 1.375)]*
(1 - (1.07*(133 - f)^2)/
10^3)*0.1^0.5 +
0.479*Exp[-9.986*
(r - 1.375)] + 0.479
But now, I don't know what your question might be.
Bobby
On Thu, 19 May 2005 03:08:49 -0400 (EDT), Paawel <fonfastik at interia.pl> wrote:
>> >> Can you post your code in "input form"?
>
> Here it is(??)
>
> ---------------F1----------------
>
> Cell[BoxData[
> StyleBox[
> RowBox[{"F1", "=",
> RowBox[{
> RowBox[{
> RowBox[{"-", "7.516"}], "*", " ",
> RowBox[{"Exp", "[",
> RowBox[{
> RowBox[{"-", "3.076"}], "*",
> RowBox[{"(",
> RowBox[{"r", "-", "1.184"}], ")"}]}], "]"}], "*",
> RowBox[{"(",
> RowBox[{"1", "-",
> RowBox[{"8.28", "*",
> SuperscriptBox["10",
> RowBox[{"-", "5"}]], "*",
> SuperscriptBox[
> RowBox[{"(",
> RowBox[{"180", " ", "-", " ", "f"}], ")"}],
> "2"]}]}], ")"}], "*",
> SuperscriptBox["1", "0.5"]}], "+",
> RowBox[{"3.758", "*",
> RowBox[{"Exp", "[",
> RowBox[{
> RowBox[{"-", "6.152"}], "*",
> RowBox[{"(",
> RowBox[{"r", "-", "1.184"}], ")"}]}], "]"}]}], "+",
> "3.92"}]}],
> "Text"]], "Input"]
>
> -----------------------F2---------------------------------
>
> Cell[BoxData[
> RowBox[{"F2", "=",
> RowBox[{
> RowBox[{
> RowBox[{"-", "0.958"}], "*", " ",
> RowBox[{"Exp", "[",
> RowBox[{
> RowBox[{"-", "4.993"}], "*",
> RowBox[{"(",
> RowBox[{"r", "-", "1.375"}], ")"}]}], "]"}], "*",
> RowBox[{"(",
> RowBox[{"1", "-",
> RowBox[{"1.07", "*",
> SuperscriptBox["10",
> RowBox[{"-", "3"}]], "*",
> SuperscriptBox[
> RowBox[{"(",
> RowBox[{"133", " ", "-", " ", "f"}], ")"}],
> "2"]}]}], ")"}], "*",
> SuperscriptBox["0.1", "0.5"]}], "+",
> RowBox[{"0.479", "*",
> RowBox[{"Exp", "[",
> RowBox[{
> RowBox[{"-", "9.986"}], "*",
> RowBox[{"(",
> RowBox[{"r", "-", "1.375"}], ")"}]}], "]"}]}], "+",
> "0.479"}]}]], "Input"]
>
>
>
>
--
DrBob at bigfoot.com
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