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Re: how to map function with over 1 arguments to list


You can use MapThread

f[x_, y_] = x + y;

in:  MapThread[f, {{1, 1}, {2, 2}}]
out:  {3, 3}

If you don't need to maintain the function definition f, you could 
simplify as follows:

in:  MapThread[ (#1+#2)&, {{1, 1}, {2, 2}}]
out: {3,3}

cheers,
lee


xun wrote:
> Hi, all,
> 
> g[x_]:=x^2;
> g/@{1,2,3} results in{1,4,9}
> 
> similarly, how to map f[x_,y_]:=x+y;
> to {1,1},{2,2}?
> 
> it seems that f/@{{1,1},{2,2}} doesn't work.
> 
> Thx.
> Xun
> 
> 
> 
> 


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