Re: plot hyperbola

*To*: mathgroup at smc.vnet.net*Subject*: [mg57311] Re: plot hyperbola*From*: Bill Rowe <readnewsciv at earthlink.net>*Date*: Tue, 24 May 2005 05:12:49 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

On 5/23/05 at 4:30 AM, bdsatish at gmail.com (bd satish) wrote: >HI, i am a beginner. Will u please tell me how to plot >hyperbola,parabola,ellipse and circle in their standard forms >x^2/a^2 + y^2/b^2 = 1 x^2/a^2 -- y^2/b^2 ==1 etc. Also how do you >plot a general curve (y versus x), say x^2 +3 x^2 y^3 +67 x^4 y^2 >+34==0 *without solving explicitly for y* ( or x) Please help The easiest way I know to do this is to use the package Graphics`ImplicitPlot. That is the following will generate the plots you asked about <<Graphics`ImplicitPlot` {a, b} = {2, 1}; ImplicitPlot[x^2/a^2 + y^2/b^2 == 1, {x, -5, 5}, Frame -> True, Axes -> None]; ImplicitPlot[x^2/a^2 - y^2/b^2 == 1, {x, -5, 5}]; ImplicitPlot[x^2 + 3 x^2 y^3 + 67 x^4 y^2 + 34 == 0, {x, -1, 1}, AspectRatio -> 1, PlotPoints -> 105]; In the last example, I've changed the aspect ratio and increased the number of plot points to get a better appearing plot. -- To reply via email subtract one hundred and four