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MathGroup Archive 2005

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Re: Two related question. Question 1

  • To: mathgroup at smc.vnet.net
  • Subject: [mg57525] Re: [mg57498] Two related question. Question 1
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Tue, 31 May 2005 04:59:31 -0400 (EDT)
  • Reply-to: hanlonr at cox.net
  • Sender: owner-wri-mathgroup at wolfram.com

f=#1^2+#2&;

c=f[#1,#2]^2&;

f[a,b]

a^2 + b

c[a,b]

(a^2 + b)^2


Bob Hanlon

> 
> From: kazimir04 at yahoo.co.uk (Kazimir)
To: mathgroup at smc.vnet.net
> Date: 2005/05/29 Sun PM 09:00:17 EDT
> Subject: [mg57525] [mg57498] Two related question. Question 1
> 
> I have two related question. Let me introduce a pure function
> 
> f = #1^2 + #2 &
> 
> Now. I want to make an operation over the function, for example to
> find its square and to call the result (the expected function f = (#1^2
> + #2)^2 & ) c:
> 
> c=f^2
> 
> However, I do not obtain this, as 
> 
> c[a,b]
> 
> does not evaluate to (a+b)^2. Can anybody advise me how to obtain
> such a function without long substitutions. I would like to obtain
> something which is made for derivatives :
> 
> In[11]:=
> Derivative[1][f]
> 
> Out[11]=
> 2 #1&
> 
> In[12]:=
> Derivative[2][f]
> 
> Out[12]=
> 2&
> 
> Regards 
> 
> Vlad
> 
> 


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