Re: V5.0 and inequalities
- To: mathgroup at smc.vnet.net
- Subject: [mg62541] Re: V5.0 and inequalities
- From: "Steve Luttrell" <steve_usenet at _removemefirst_luttrell.org.uk>
- Date: Sun, 27 Nov 2005 02:40:58 -0500 (EST)
- References: <dm94t5$6l6$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
You could evaluate the following expression to see how the Boolean value of
your expression varies with x.
TableForm[Table[{x, (x + 1)/(x - 2) > 1}, {x, 1, 3, 0.1}]]
or you could simply evaluate the following plot to see the numerical
dependence of the l.h.s. minus the r.h.s.
Plot[(x + 1)/(x - 2) - 1, {x, 1, 3}]
Steve Luttrell
<ivan.svaljek at gmail.com> wrote in message news:dm94t5$6l6$1 at smc.vnet.net...
> Is there a way to get an answer to at least the simplest form of
> inequalities ?
>
> x+1
> ------ > 1
> x-2
>