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MathGroup Archive 2005

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Re: V5.0 and inequalities

  • To: mathgroup at smc.vnet.net
  • Subject: [mg62541] Re: V5.0 and inequalities
  • From: "Steve Luttrell" <steve_usenet at _removemefirst_luttrell.org.uk>
  • Date: Sun, 27 Nov 2005 02:40:58 -0500 (EST)
  • References: <dm94t5$6l6$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

You could evaluate the following expression to see how the Boolean value of 
your expression varies with x.

TableForm[Table[{x, (x + 1)/(x - 2) > 1}, {x, 1, 3, 0.1}]]

or you could simply evaluate the following plot to see the numerical 
dependence of the l.h.s. minus the r.h.s.

Plot[(x + 1)/(x - 2) - 1, {x, 1, 3}]

Steve Luttrell

<ivan.svaljek at gmail.com> wrote in message news:dm94t5$6l6$1 at smc.vnet.net...
> Is there a way to get an answer to at least the simplest form of
> inequalities ?
>
> x+1
> ------ > 1
> x-2
> 



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