       Re: 3D plot question

• To: mathgroup at smc.vnet.net
• Subject: [mg62656] Re: 3D plot question
• Date: Wed, 30 Nov 2005 00:07:42 -0500 (EST)
• Sender: owner-wri-mathgroup at wolfram.com

```On 11/29/05 at 4:44 AM, tma at nus.edu.sg (Tun Myint Aung) wrote:

>When I plot a 3D plot in mathematica, I found that some part of the
>surface has been cut off in the graph. For example,

>z = x^5*y

>Plot3D[z, {x, -1, 1}, {y, -1, 1}, PlotPoints -> 40,

>Mesh -> False, BoxRatios -> {1, 1, 0.4}]

>Mathematica plot for z values only in the range -0.2 to 0.2.
>Actually when x=1, y=1, z value will be 1. But in the graph, the
>surface goes flat for z>0.2.Why? How can I get the graph for full
>range of z?

Mathematica has an internal algorithm used in plotting functions that is designed to scale the plot so has to show the most interesting portion of the plot. Obviously, there is no way Mathematica can know what portion of the plot is most interesting to you. So, it should not be surprising what is shown in a plot is clipped or not as expected. What should be suprising is the amount of times Mathematica's algorithm gets it right.

In any case, the solution is to include the option PlotRange->All which causes Mathematica to scale the plot so that all of the values show up.

Note, this aspect of Mathematica can be particularly insidious when using ListPlot. For example, consider the following plot

ListPlot[Join[Table[Random[], {50}], {1000}, Table[Random[], {50}]]];

The existence of the one odd large value is not apparent. Yet such values could be the most important points in a data set.

The problem with using PlotRange->All is illustrated by the following plot

ListPlot[Join[Table[Random[], {50}] + Range@50, {10000}, Table[Random[], {
50}] + Range@50 + 50], PlotRange -> All];

Here the general linear trend is obscured by forcing Mathmatica to include all of the data.

The point is there is no set of options that can be trusted to always provide a good view of your data.
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