MathGroup Archive 2005

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the faster way to find repeated sublists


i'm newbie
with a stupid problem

a function for find repetead sublist in faster way

ex
f[{1,2,1,2,1,2},{1,2}]-> True cause {1,2} is repated three times
f[{1,2,3,1,2,3},{1,2,3}]-> True cause {1,2,3} is repeated two times
f[{1,2,1,2,3},{1,2}]->False cause after two {1,2} there is another
symbol.

True if the second list in containes many times exactly in first list
False otherwise.


bye everyone and sorry for my stupidity.

giampiero


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