Re: problem solving polynomial equations
- To: mathgroup at smc.vnet.net
- Subject: [mg61331] Re: [mg61306] problem solving polynomial equations
- From: Andrzej Kozlowski <akoz at mimuw.edu.pl>
- Date: Sun, 16 Oct 2005 00:17:47 -0400 (EDT)
- References: <200510140953.FAA28482@smc.vnet.net> <200510150222.WAA17287@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
On 15 Oct 2005, at 11:22, wtplasar at ehu.es wrote: > > Hi, > > > I have two equations. The first one is > > eqy=(y*(3*b^2 + 12*b*y^2 + 12*y^4 + 3*b^2*z^4 + 4*b*y^2*z^4 + > 3*r*y*Sqrt[4*y^4 + 4*b*y^2*(1 + z^4) + b^2*(1 + 3*z^4) + z^2*(8*b*y^2 > + 4*y^4 + b^2*(3 + z^4))*Sign[k]]* > Sign[s] + z^2*Sign[k]*(6*b^2 + 16*b*y^2 + 8*y^4 + r*y*Sqrt[4*y^4 + > 4*b*y^2*(1 + z^4) + b^2*(1 + 3*z^4) + z^2*(8*b*y^2 + 4*y^4 + b^2*(3 + > z^4))*Sign[k]]* > Sign[s])))/(3*(3*b^2 + 8*b*y^2 + 4*y^4 + 3*b^2*z^4 + 2*b*(3*b + > 4*y^2)*z^2*Sign[k] + > 2*r*y*Sqrt[4*y^4 + 4*b*y^2*(1 + z^4) + b^2*(1 + 3*z^4) + z^2* > (8*b*y^2 + 4*y^4 + b^2*(3 + z^4))*Sign[k]]*Sign[s])); > > > and the second one is > > eqz=(y*z*(4*b*y + 8*y^3 + 4*b*y*z^4 + r*Sqrt[4*y^4 + 4*b*y^2*(1 + z^4) > + b^2*(1 + 3*z^4) + z^2*(8*b*y^2 + 4*y^4 + b^2*(3 + z^4))*Sign[k]] > *Sign > [s] + > z^2*Sign[k]*(8*b*y + 8*y^3 + r*Sqrt[4*y^4 + 4*b*y^2*(1 + z^4) + > b^2* > (1 + 3*z^4) + z^2*(8*b*y^2 + 4*y^4 + b^2*(3 + z^4))*Sign[k]]*Sign > [s])))/ > (3*(3*b^2 + 8*b*y^2 + 4*y^4 + 3*b^2*z^4 + 2*b*(3*b + 4*y^2)*z^2*Sign > [k] + > 2*r*y*Sqrt[4*y^4 + 4*b*y^2*(1 + z^4) + b^2*(1 + 3*z^4) + z^2* > (8*b*y^2 + 4*y^4 + b^2*(3 + z^4))*Sign[k]]*Sign[s])); > > Now when I do > > Solve[{eqy == 0, eqzsubs == 0}, {y, z}] /. Sign[s]^2 -> 1 > > I get the result fairly quickly, but if I do > > Solve[{Numerator[eqy]== 0, Numerator[eqz] == 0}, {y, z}]/. Sign[s]^2 - > >> 1 >> > > it seems to get stuck. I may get an answer eventually, but it seemed > to be taking too long and aborted it. > > Any clues? Thanks. > > Ruth > > What is eqzsubs? Andrzej Kozlowski Tokyo, Japan
- References:
- Re: Solving Diophantine Equations
- From: Andrzej Kozlowski <andrzej@yhc.att.ne.jp>
- problem solving polynomial equations
- From: wtplasar@ehu.es
- Re: Solving Diophantine Equations