Mathematica 9 is now available
Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2005
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2005

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Unsorted Union

  • To: mathgroup at smc.vnet.net
  • Subject: [mg61485] Re: Unsorted Union
  • From: "dkr" <dkrjeg at adelphia.net>
  • Date: Wed, 19 Oct 2005 23:07:42 -0400 (EDT)
  • References: <dj4p6t$gpt$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Robert,

Consider the first element of x, call it x1. Using the definition of
the function f, it will generate the value x1 (and also store the value
f[x1] as Sequence[]).  Note that since this is the first time x1 has
been encountered in the mapping operation, there won't be a previously
stored value of f[x1].  Now as we proceed through the elements of x,
suppose we encounter x1 again.  Then mathematica will already have
stored the value f[x1], and will use it to generate the value
Sequence[], which effectively removes that x1 from the list.

Robert Schoefbeck wrote:
> Hello all,
>
> in the help section i found the following thing:
>
> UnsortedUnion[x_] := Module[{f}, f[y_] := (f[y] = Sequence[]; y); f/@x]
>
> It does just what it says:
> UnsortedUnion[{a,c,b,d,a,b}]={a,c,b,d}
>
> (ordinary Union would Sort the result)
>
> my question is: How does the definition work? I know all the syntax
> and i have been using these concepts for for some time now. But i cant
> figure out what this definition does.
> 
> Robert


  • Prev by Date: Re: Unsorted Union
  • Next by Date: Re: Display sound but suppress graphics
  • Previous by thread: Re: Unsorted Union
  • Next by thread: Re: Unsorted Union