Apply and up/down value questions

*To*: mathgroup at smc.vnet.net*Subject*: [mg61533] Apply and up/down value questions*From*: "Matt" <anonmous69 at netscape.net>*Date*: Sat, 22 Oct 2005 00:35:18 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

Hello, Again, I'm working my way through some of the programming examples in Michael Trott's Programming Guidebook, and there's behaviour that I cannot figure out. I've been over and over section A.5.2 and 2.5.10 in the Mathematica Book, but I still don't understand up values when applied to functions with more than one argument. Also, I had a question about level specification, which I couldn't figure out even after looking at section A.3.6. Any help is appreciated. First the upvalue questions: I don't understand the point of using TagSet as opposed to UpSet: e.g. in Michael Trott's Programming Guidebook on page 318 he states: "For functions with several arguments, the information can be associated with a certain prescribed argument rather than with all arguments at the first level." However, I don't see any difference in functionality between this: x /: Plus[x, y_] = y; Plus[x, 7] ??x ??y and this (after clearing x and y) Plus[x, y_] ^:= y Plus[x, 7] ??x ??y Also, I'm stumped on this particular wording in the TagSet documentation: "If f appears several times in lhs, then f/: lhs = rhs associates the assignment with each occurrence" What does this really mean? As regards Apply: Is it true that Apply[newHead, expr, 1] and Apply[newHead, expr, {1}] will always be the same result given that the other two arguments are identical? By definition, a level specification of n applies to levels 1 through n. I have found that if I do something like Apply[newHead, expr, -2], that what I actually end up with seems to be equivalent to newExpr = Apply[newHead, expr, {1}] followed by Apply[newHead, newExpr, {-2}]. Here is an example: Cell[BoxData[{ RowBox[{ RowBox[{"a1", " ", "=", " ", RowBox[{"Array", "[", RowBox[{"\[DoubleStruckR]", ",", RowBox[{"{", RowBox[{"2", ",", "2"}], "}"}], ",", RowBox[{"{", RowBox[{"2", ",", "4"}], "}"}]}], "]"}]}], ";"}], "\[IndentingNewLine]", RowBox[{"MatrixForm", "[", "a1", "]"}], "\[IndentingNewLine]", RowBox[{ RowBox[{"a11", " ", "=", " ", RowBox[{"Apply", "[", RowBox[{"newHead", ",", "a1", ",", RowBox[{"{", "1", "}"}]}], "]"}]}], ";"}], "\[IndentingNewLine]", RowBox[{"MatrixForm", "[", "a11", "]"}], "\[IndentingNewLine]", RowBox[{ RowBox[{"a12", " ", "=", " ", RowBox[{"Apply", "[", RowBox[{"newHead", ",", "a11", ",", RowBox[{"{", RowBox[{"-", "2"}], "}"}]}], "]"}]}], ";"}], "\[IndentingNewLine]", RowBox[{"MatrixForm", "[", "a12", "]"}], "\[IndentingNewLine]", RowBox[{ RowBox[{"a13", " ", "=", " ", RowBox[{"Apply", "[", RowBox[{"newHead", ",", " ", "a1", ",", " ", RowBox[{"-", "2"}]}], "]"}]}], ";"}], "\[IndentingNewLine]", RowBox[{"MatrixForm", "[", "a13", "]"}]}], "Input"] What is the general rule, or am I just misusing the level specification in Apply? And finally, a question on modified built in functions: In Michael Trott's Programming Guidebook, on page 311, he uses the following construct to remove a downvalue that had been specified for the Cos and Sin functions: Unprotect[Cos]; Clear[Cos]; Protect[Cos]; {Cos} I've noticed that if I omit the last line (i.e. {Cos}), that it still works. What is the point of the last line? Thanks very much, Matt

**aggregation of related elements in a list**

**Re: refer to the result of FindRoot[ ]**

**Re: Re: aggregation of related elements in a list**

**Re: Apply and up/down value questions**