Re: Set construction with condition
- To: mathgroup at smc.vnet.net
- Subject: [mg61575] Re: Set construction with condition
- From: "Valeri Astanoff" <astanoff at yahoo.fr>
- Date: Sat, 22 Oct 2005 05:11:20 -0400 (EDT)
- References: <dj71qk$cmn$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
My solution :
myStringJoin[a_,b_,c_,d_]/;Count[{a,b,c,d},"1"]>2:=Sequence[];
myStringJoin[a_,b_,c_,d_]:=StringJoin[a,b,c,d];
Flatten[Outer[myStringJoin,
{"1","X","2"},{"1","X","2"},{"1","X","2"},{"1","X","2"}]]
v.a.