[Date Index]
[Thread Index]
[Author Index]
Re: A Su Doku solver
*To*: mathgroup at smc.vnet.net
*Subject*: [mg60558] Re: [mg60534] A Su Doku solver
*From*: Zhe Hu <iamhuzhe at gmail.com>
*Date*: Tue, 20 Sep 2005 05:19:21 -0400 (EDT)
*References*: <200509191007.GAA25694@smc.vnet.net>
*Reply-to*: iamhuzhe at gmail.com
*Sender*: owner-wri-mathgroup at wolfram.com
It's great to see another one-page solution.(There is one interesting
solution in J language at http://www.vector.org.uk/archive/v214/sudoku.htm)
I tried one from www.sudoku.com <http://www.sudoku.com>
myGrid = {{0, 6,
0, 1, 0, 4, 0, 5, 0}, {0, 0, 8, 3, 0, 5, 6, 0, 0}, {2, 0, 0,
0, 0, 0, 0, 0, 1}, {8, 0, 0, 4, 0, 7, 0, 0, 6}, {0, 0, 6,
0, 0, 0, 3, 0, 0}, {7, 0, 0, 9, 0, 1, 0, 0, 4}, {5, 0, 0,
0, 0, 0, 0, 0, 2}, {0, 0, 7, 2, 0, 6, 9, 0, 0}, {0, 4, 0,
5, 0, 8, 0, 7, 0}}
It failed to fill in each cell.
On 9/19/05, Valeri Astanoff <astanoff at yahoo.fr> wrote:
>
> Dear group,
>
> Here is my little Mathematica "Su Doku" solver :
>
> In[1]:=sudoku[m_List?MatrixQ /;Length[m] == 9 ]:=
> FixedPoint[doku,m];
>
> doku[m_List?MatrixQ /; Length[m] == 9]:=
> Module[{mi,r,sq,sel},
> mi=MapIndexed[Prepend[#2,#1]&,m,{2}];
> r={0,i_Integer,j_Integer} :>
> {sq =(Which[
> 1 <= i <= 3 && 1 <= j <= 3, mi[[{1,2,3}]] [[All,{1,2,3}]],
> 1 <= i <= 3 && 4 <= j <= 6, mi[[{1,2,3}]] [[All,{4,5,6}]],
> 1 <= i <= 3 && 7 <= j <= 9, mi[[{1,2,3}]] [[All,{7,8,9}]],
> 4 <= i <= 6 && 1 <= j <= 3, mi[[{4,5,6}]] [[All,{1,2,3}]],
> 4 <= i <= 6 && 4 <= j <= 6, mi[[{4,5,6}]] [[All,{4,5,6}]],
> 4 <= i <= 6 && 7 <= j <= 9, mi[[{4,5,6}]] [[All,{7,8,9}]],
> 7 <= i <= 9 && 1 <= j <= 3, mi[[{7,8,9}]] [[All,{1,2,3}]],
> 7 <= i <= 9 && 4 <= j <= 6, mi[[{7,8,9}]] [[All,{4,5,6}]],
> 7 <= i <= 9 && 7 <= j <= 9, mi[[{7,8,9}]] [[All,{7,8,9}]],
> True,Print["err"]] // Flatten[#,1]&)[[All,1]] // Union;
>
> sel := Complement[Range[9], mi[[i,All,1]], mi[[All,j,1]],sq];
> If[Length[sel] == 1, sel[[1]],0],i,j};
> (mi//.r)[[All,All,1]]
> ];
>
> A grid example :
>
> In[3]:=
> myGrid={{0,8,0,0,0,1,6,0,0},
> {0,7,0,4,0,0,0,2,1},
> {5,0,0,3,9,6,0,0,0},
> {2,0,4,0,5,0,1,3,0},
> {0,0,8,9,0,7,5,0,0},
> {0,5,7,0,3,0,9,0,2},
> {0,0,0,5,6,3,0,0,9},
> {3,1,0,0,0,2,0,5,0},
> {0,0,5,8,0,0,0,4,0}};
>
> In[4]:=
> sudoku[myGrid]//Timing
>
> Out[4]=
> {0.016 Second,
> {{4,8,3,2,7,1,6,9,5},
> {9,7,6,4,8,5,3,2,1},
> {5,2,1,3,9,6,4,7,8},
> {2,9,4,6,5,8,1,3,7},
> {1,3,8,9,2,7,5,6,4},
> {6,5,7,1,3,4,9,8,2},
> {8,4,2,5,6,3,7,1,9},
> {3,1,9,7,4,2,8,5,6},
> {7,6,5,8,1,9,2,4,3}}}
>
>
> It's more fun to compete : does any one have a shorter and/or faster
> solution?
>
>
> v.a.
>
>
Prev by Date:
**Re: Differences between recursions and limit**
Next by Date:
**Re: Re: Complete solution to a modular System of equations ( Correction)**
Previous by thread:
**Re: A Su Doku solver**
Next by thread:
**Re: A Su Doku solver**
| |