Re: For Loop problem
- To: mathgroup at smc.vnet.net
- Subject: [mg65614] Re: [mg65595] For Loop problem
- From: "Carl K. Woll" <carlw at wolfram.com>
- Date: Tue, 11 Apr 2006 04:04:22 -0400 (EDT)
- References: <200604100631.CAA14834@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Rob wrote:
> I've got to manipulate some signed 12bit integer numbers from a file and
> apparently Mathematica only handles 8 and 16 bit signed numbers
> (probably for a very good reason). So I bring them in as 16 bits (and
> they're stored that way with a leading zero nibble) and then I have to
> do the following to make sense of them. I really don't know why this
> code works but it does.
>
> For[i = 1, i < Length[y], i++, If[y[[i]] > 2048, y[[i]] =
> y[[i]] - 2048, y[[i]] = y[[i]] + 2048]];
>
> So to my question: once again I had to resort to a For loop to pull this
> off and I know this is a no-no. But I'm so clueless about Mathematica
> that I've never come up with a more sophisticated method after a year or
> so of thinking about it. Can someone help (as they usually can)?
>
> Thanks, Rob
Assuming that your data are all integers between -2047 and 6144, you
could use Mod. Here is some data:
In[11]:=
data=Table[Random[Integer,{-2047,6144}],{10}]
Out[11]=
{5745,-1569,4196,3299,5796,1621,596,-1299,1074,3547}
Your method (modified with <= instead of < so that the last entry is
processed):
In[12]:=
y=data;
For[i=1,i<=Length[y],i++,
If[y[[i]]>2048,y[[i]]=y[[i]]-2048,y[[i]]=y[[i]]+2048]];
y
Out[14]=
{3697,479,2148,1251,3748,3669,2644,749,3122,1499}
Using Mod:
In[15]:=
Mod[2048+data,4096,1]
Out[15]=
{3697,479,2148,1251,3748,3669,2644,749,3122,1499}
If you want 2048->0 instead of 2048->4096, use
Mod[2048+data,4096]
Carl Woll
Wolfram Research
- References:
- For Loop problem
- From: Rob <rob@piovere.com>
- For Loop problem