3D ContourGraphics alternative

*To*: mathgroup at smc.vnet.net*Subject*: [mg65683] 3D ContourGraphics alternative*From*: "vasil michev" <michev at gmail.com>*Date*: Fri, 14 Apr 2006 04:32:07 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

Hello, I need to plot a function of 3 parameters, and later examine different contours of it. To do so, I've already downloaded and tried ImplicitPlot3D and ContourPlot3D, but once I have the plot, say p1 = ImplicitPlot3D[z^2 == 1 - (2 - Sqrt[x^2 + y^2])^2, {x, -3, 3}, {y, -3, 3}, {z, -1, 1}, PlotPoints -> {15, 15, 10}, Passes -> Automatic] I want to be able to work with the 'pl1' plot. With the 'ordinary' Plot3D command the outpur it SurfaceGraphics and I can convert it, or immediately display N contours of it on a single plot using the ContourGraphics function. For example: Show[ContourGraphics[Out[80]], ColorFunction -> Hue, ColorFunctionScaling -> True, ContourShading -> False, Contours -> 11, PlotRange -> {{-10, 10}, {1, 10}, {0.39999, .4}}] But when using ContourPlot3D or ImplicitPlot3D packages the output is more general - Graphics3D, and I cant simply do the trick. Can anyone help me out, is there any package that will do the trick or any other way you can think of doing this? I tried making number of plots with various limitation for z-range, say Show[p1, PlotRange -> {-.00001, 0}, Axes -> True] and that seems to do what I want, but problems occur when I try to convert the output to "ordinary" Graphics object - the range/points are all wrong, probalby scaled (they vary from 0 to 1 only) (If you cant understand me just try the following: p1 = ImplicitPlot3D[E^z Cos[x] == Cos[y], {x, -6, 6}, {y, -6, 6}, {z, -6, 6}, PlotPoints -> {16, 16, 12}, Passes -> 4] pp1 = Show[p1, PlotRange -> {-.00001, 0}, Axes -> True] Show[Graphics[pp1], Axes -> True, PlotRange -> All] and look at the later 2 graphs - they're not quite the same... any help working around this will be much appretiated too) thanks in advance for any help