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MathGroup Archive 2006

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Re: Using implicit information about row indices

  • To: mathgroup at smc.vnet.net
  • Subject: [mg68328] Re: [mg68254] Using implicit information about row indices
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Tue, 1 Aug 2006 06:59:59 -0400 (EDT)
  • Reply-to: hanlonr at cox.net
  • Sender: owner-wri-mathgroup at wolfram.com

sam[L_List] := Module[{sL=Split[L, #1[[1]]<#2[[1]]&]},
      SparseArray[Flatten[MapIndexed[Prepend[#1,#2[[1]]]&, sL,{2}],
      1]/.{row_, col_, val_}:>({row,col}->val)]];

L={{1,a},{2,b},{1,c},{2,d},{3,e},{4,f},{2,g},{3,h},{4,i},{3,k},{4,l},{5,m},{4,
      n},{5,p}};

sam[L]//Normal

{{a, b, 0, 0, 0}, {c, d, e, f, 0}, {0, g, h, i, 0}, 
  {0, 0, k, l, m}, {0, 0, 0, n, p}}


Bob Hanlon

---- "Diamond wrote: 
> I am wanting to fill a square matrix M (say, r by r)  using information from
> a list, L.
>  The list L is also of length r, but is not a square matrix. It contains
> lists of ordered pairs {col, num}
> It typically looks something like this; I have arranged it into rows so that
> it is more obvious
> {
>   {{1, a}, {2, b}},
> 
>   {{1, c}, {2, d}, {3, e}, {4, f}},
> 
>  {{2, g}, {3, h}, {4, i}},
> 
>  {{3, k}, {4, l}, {5,m}},
> 
>  {{4, n}, {5, p}}
> 
> }
> 
> Now what I am trying to do is, for example, set M[[1,1]]=a, M[[1,2]]=b,
> M[[2,1]]=c, M[[2.2]]=d, M[[2,3]]=e and so forth, and leave (or set) all the
> other entries in M to zero. The row information for M is implicit in the
> structure of the list L; additionally, the column indices as they appear
> within sublist of L are guraranteed to be sequential. It seems with all this
> info, there should be an easy way to fill M correctly, but I have struggled
> without success to do anything other than an iterative process with Do[]. I
> would appreciate any guidance you might have.
> 
> Thank you.
> 
> Mark Diamond
> 


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