Re: Using implicit information about row indices
- To: mathgroup at smc.vnet.net
- Subject: [mg68321] Re: [mg68254] Using implicit information about row indices
- From: János <janos.lobb at yale.edu>
- Date: Tue, 1 Aug 2006 06:59:50 -0400 (EDT)
- References: <200607310745.DAA26729@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
On Jul 31, 2006, at 3:45 AM, Diamond, Mark wrote:
> I am wanting to fill a square matrix M (say, r by r) using
> information from
> a list, L.
> The list L is also of length r, but is not a square matrix. It
> contains
> lists of ordered pairs {col, num}
> It typically looks something like this; I have arranged it into
> rows so that
> it is more obvious
> {
> {{1, a}, {2, b}},
>
> {{1, c}, {2, d}, {3, e}, {4, f}},
>
> {{2, g}, {3, h}, {4, i}},
>
> {{3, k}, {4, l}, {5,m}},
>
> {{4, n}, {5, p}}
>
> }
>
> Now what I am trying to do is, for example, set M[[1,1]]=a, M[[1,2]]
> =b,
> M[[2,1]]=c, M[[2.2]]=d, M[[2,3]]=e and so forth, and leave (or set)
> all the
> other entries in M to zero. The row information for M is implicit
> in the
> structure of the list L; additionally, the column indices as they
> appear
> within sublist of L are guraranteed to be sequential. It seems with
> all this
> info, there should be an easy way to fill M correctly, but I have
> struggled
> without success to do anything other than an iterative process with
> Do[]. I
> would appreciate any guidance you might have.
>
> Thank you.
>
> Mark Diamond
>
>
>
Here is a newbie approach:
In[9]:=
lst = {{{1, a}, {2, b}},
{{1, c}, {2, d}, {3, e},
{4, f}}, {{2, g}, {3, h},
{4, i}}, {{3, k}, {4, l},
{5, m}}, {{4, n}, {5, p}}}
In[23]:=
Normal[SparseArray[
Flatten[
(Table[Flatten[
{Flatten[Position[
lst, #1]], #1[[ii,
1]]}] -> #1[[ii,
2]], {ii, 1,
Length[#1]}] & ) /@
lst]]]
Out[23]=
{{a, b, 0, 0, 0}, {c, d, e,
f, 0}, {0, g, h, i, 0},
{0, 0, k, l, m},
{0, 0, 0, n, p}}
János
----------------------------------------------
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corpse.
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