Re: near Planck's mass

*To*: mathgroup at smc.vnet.net*Subject*: [mg68459] Re: near Planck's mass*From*: Roger Bagula <rlbagula at sbcglobal.net>*Date*: Sun, 6 Aug 2006 02:56:29 -0400 (EDT)*References*: <eb1jsc$e8b$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

Another way to get it this kind of mass with a Sqrt[2] factor instead of Sqrt[3]: (* Schwartzschild's singularity radius*) r=2*m*G/c^2 (*with electronmagnetiic radius*) Solve[2*m*G/c^2=e^2/(m*c^2),m] This method is more like the Planck derivation at r=h/(m*c) Roger Bagula wrote: >Back about 1987 or before > I was studying gravitation and quantum mechanics >and I came across this: >(* Classical electromagnetic radius*) >r = e^2/(m*c^2) >(* Riemannian Curvature*) >R = -2/r^2 >(* 3 space volume*) >V = (4*Pi/3)*r^3 >(*scalar energy densidty*) >T = m*c^2/V >(* solution for R = -8Pi*G*T(v, v) : scalar reduction of Einstein's > general relativity*) >Solve[R + (8*Pi*G/c^4)*T == 0, m] >e = 4.80325*10^(-10) >G = 6.6732*10^(-8) >(* mass in grams*) >m = e/Sqrt[3*G] >1.073513458510097`*10^-6 > >At the time I hadn't run into Planck's mass. >If you put in > r=h/(m*c) >in this calculation you get a version of the Planck mass. > >I was wondering if this was a well known calculation like Planck's mass? >Roger > > >