Newbie question about column sums of arrays
- To: mathgroup at smc.vnet.net
- Subject: [mg68508] Newbie question about column sums of arrays
- From: "George W. Gilchrist" <gwgilc at wm.edu>
- Date: Tue, 8 Aug 2006 06:29:03 -0400 (EDT)
- Sender: owner-wri-mathgroup at wolfram.com
I have spent several hours trying to find an answer to what must be an incredibly simple problem: how to sum the columns of an array containing a random mix of +1 and -1s. For example: In[7]:= AA1=Array[x, {4,4}]/. x:> (-1)^Random[Integer] Out[7]= \!\(\*FormBox[ RowBox[{"(", "\[NoBreak]", GridBox[{ {\(1[1, 1]\), \(1[1, 2]\), \(\((\(-1\))\)[1, 3]\), \(1[1, 4] \)}, {\(1[2, 1]\), \(1[2, 2]\), \(\((\(-1\))\)[ 2, 3]\), \(\((\(-1\))\)[2, 4]\)}, {\(1[3, 1]\), \(\((\(-1\))\)[3, 2]\), \(1[3, 3]\), \(1[3, 4] \)}, {\(\((\(-1\))\)[4, 1]\), \(1[4, 2]\), \(1[4, 3]\), \(\((\(-1\))\)[4, 4]\)} }, RowSpacings->1, ColumnSpacings->1, ColumnAlignments->{Left}], "\[NoBreak]", ")"}], TraditionalForm]\) In[8]:= Total[AA1] Out[8]= {(-1)[4,1]+1[1,1]+1[2,1]+1[3,1], (-1)[3,2]+1[1,2]+1[2,2]+1[4,2], (-1)[1,3]+(-1)[2,3]+1[3,3]+1[4,3], (-1)[2,4]+(-1)[4,4]+1[1,4]+1[3,4]} So, Total[] seems to do the right thing, but I cannot get the actual sums as real numbers, only this rather verbose representation. I have searched the manuals for just about everything I can think of with no luck. So, thanks for any help you can give me. Cheers, George .................................................................. George W. Gilchrist Email #1: gwgilc at wm.edu Department of Biology, Box 8795 Email #2: kitesci at cox.net College of William & Mary Phone: (757) 221-7751 Williamsburg, VA 23187-8795 Fax: (757) 221-6483 http://gwgilc.people.wm.edu/
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