RE: Re: for higher dimensions?

*To*: mathgroup at smc.vnet.net*Subject*: [mg68585] RE: [mg68532] Re: for higher dimensions?*From*: "Tony Harker" <a.harker at ucl.ac.uk>*Date*: Fri, 11 Aug 2006 04:39:47 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

I don't think there's any alternative to recasting your problem as a conventional eigenproblem -- but it's not too messy to do so. For example: mm = Array[a, {2, 3, 4, 5}] MatrixForm[newm = Flatten[Transpose[Flatten[mm, 1], {3, 1, 2}], 1]] Then a judicious application of Partition[] to the result will get you your A matrix. Tony Harker Dr A.H. Harker Department of Physics and Astronomy University College London Gower Street London WC1E 6BT ]->-----Original Message----- ]->From: AES [mailto:siegman at stanford.edu] To: mathgroup at smc.vnet.net ]->Subject: [mg68585] [mg68532] Re: for higher dimensions? ]-> ]->In article <eb9p00$srh$1 at smc.vnet.net>, ]-> "Adriano Pascoletti" <pascolet at dimi.uniud.it> wrote: ]-> ]->> Yes. Use Eigensystem. ]->> For instance ]->> ]->> M = {{2, 0, -3}, {3, 5, 6}, {1, 1, -1}};esys = Eigensystem[M]; ]->> ]-> ]->Thanks -- but this, in my interpretation at least, is a 3 X ]->3 but still ]->*two-dimensional* (rows and columns) matrix. ]-> ]->My current task is to find eigensolutions to a problem that ]->might be written most conveniently, with it's indices shown ]->explicitly, as ]-> ]-> M_{i,j,m,n} A_{m,n} = lambda A_{i,j} ]-> ]->with M known and the objective being find a set of ]->eigenvalues lambda[k] and "eigenmatrices" A_{i,j}[k] that ]->satisfy this equation. ]-> ]->