RE: Product over an arbitrary index.

*To*: mathgroup at smc.vnet.net*Subject*: [mg68696] RE: [mg68683] Product over an arbitrary index.*From*: "David Park" <djmp at earthlink.net>*Date*: Thu, 17 Aug 2006 04:17:54 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

How do indexes enter into your expression? Do you mean f[i,j]? What exactly is the definition of your product? Do you mean something like the following, where I have set m = 5? Times @@ Flatten[Outer[f[#1, #2] &, {1, 4, 3}, Range[5]]] f[1, 1] f[1, 2] f[1, 3] f[1, 4] f[1, 5] f[3, 1] f[3, 2] f[3, 3] f[3, 4] f[3, 5] f[4, 1] f[4, 2] f[4, 3] f[4, 4] f[4, 5] The answer to the second question is yes, but it would be helpful if you gave a specific example. David Park djmp at earthlink.net http://home.earthlink.net/~djmp/ From: quantieny at gmail.com [mailto:quantieny at gmail.com] To: mathgroup at smc.vnet.net I have a function f(x,y) that I would like to compute the product over indices i,j where i goes from an arbitrary list {1,4,3} and j goes 1 to m. Is this possible in mathematica the function Product itself seems to only work over a continous sequence and it is not clear how I can use two set of indices. Additionally can I specify the product over an intersection or complement of a list?. Thanks, K Frou