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Re: Trigonometric simplification
*To*: mathgroup at smc.vnet.net
*Subject*: [mg68890] Re: Trigonometric simplification
*From*: "Dana DeLouis" <dana.del at gmail.com>
*Date*: Tue, 22 Aug 2006 05:20:29 -0400 (EDT)
*Sender*: owner-wri-mathgroup at wolfram.com
> r=Tan[a]^2/(Sec[a]^2)^(3/2)
> simplifying that to
> r=Cos[a]*Sin[a]^2
r = Tan[a]^2/(Sec[a]^2)^(3/2);
Hi. Just one of a few ways. With a Sqrt on Sec[a], try to find values of 'a
where Sec[a] is positive.
Since I've forgotten what they are...
Plot[Sec[a], {a, -Pi, Pi},
Ticks -> {Range[-Pi, Pi, Pi/4], Automatic}];
Therefore:
Assuming[{-Pi/2 < a < Pi/2}, Simplify[r]]
Cos[a]*Sin[a]^2
--
HTH. :>)
Dana DeLouis
Windows XP, Mathematica 5.2
<carlos at colorado.edu> wrote in message news:ecbnnc$r29$1 at smc.vnet.net...
> As an intermediate result of some calculations I have
> the expression
>
> r=Tan[a]^2/(Sec[a]^2)^(3/2)
>
> where a is real. How can I coerce Mathematica into
> simplifying that to
>
> r=Cos[a]*Sin[a]^2
>
> Both Simplify and FullSimplify with assumptions on a
> fail to get the simpler form.
>
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