Re: How to handle Arrays that has functional parameters:

*To*: mathgroup at smc.vnet.net*Subject*: [mg68953] Re: How to handle Arrays that has functional parameters:*From*: Bill Rowe <readnewsciv at earthlink.net>*Date*: Fri, 25 Aug 2006 05:35:08 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

On 8/23/06 at 7:15 AM, gopinathv at ou.edu (Gopinath Venkatesan) wrote: >If we have to define an array but also work as a function, how do we >define them? >For example, consider the following: > >\!\(\(func1 = Table[a[i, j], {i, 3}, {j, 3}];\)\[IndentingNewLine] >\(func2[s_, t_, i_, j_] := \(s\^i\) t\^j;\)\[IndentingNewLine] >\(Do[func1[\([i, j]\)] = func2[s, t, i, j], {i, 3}, {j, >3}];\)\[IndentingNewLine] func1 // MatrixForm\) >Where I defined func1 to be an array, and func2 to be a function, >and then assigned the func1 elements using func2 relation. When you do: func1 = Table[a[i, j], {i, 3}, {j, 3}]; you are defining func1 to be an array where each element is the function a evaluated at the array indices. Is this what you intended? Once you have defined func1 it seems you want now define function a to be as you have defined func2. If I have this correct, it seems simple pattern matching would be effective here, i.e., In[14]:= (#1 /. a[i_, j_] :> s^i*t^j & ) //@ func1 Out[14]= {{s*t, s*t^2, s*t^3}, {s^2*t, s^2*t^2, s^2*t^3}, {s^3*t, s^3*t^2, s^3*t^3}} -- To reply via email subtract one hundred and four