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Re: summing a series in mathematica
*To*: mathgroup at smc.vnet.net
*Subject*: [mg64172] Re: summing a series in mathematica
*From*: Paul Abbott <paul at physics.uwa.edu.au>
*Date*: Fri, 3 Feb 2006 01:04:04 -0500 (EST)
*Organization*: The University of Western Australia
*References*: <drf72r$ekh$1@smc.vnet.net>
*Sender*: owner-wri-mathgroup at wolfram.com
In article <drf72r$ekh$1 at smc.vnet.net>, Patrik <hosanagar at gmail.com>
wrote:
> I am trying to sum a function f(R) but want to specify an assumption for
> values one of the parameters can take. Specifically :
>
> f = Q!/(R! (Q - R)!) (g ^ R) ((1 - g)^(Q - R)) (P(1 + 2 R d - P)/(1 + R d))
>
> where g is a CDF and thus lies between 0 and 1. I wanted to get a simplified
> expression for Sum(f) where R goes from 1 to Q but want the system to account
> for the constraint on g. I tried:
>
> FullSimplify[Sum[f,{R,Q}], {R, Q}], {g < 1, g > 0}]
You have repeated {R,Q} here and this code does not work as written.
Entering the following does work (it is safer to use lowercase symbols):
$Assumptions = {0 < g < 1};
Sum[q!/(r! (q - r)!) (g ^ r) ((1 - g)^(q - r)) (p (1 + 2 d r - p)/
(1 + d r)), {r, 1, q}]
an expression involving a Hypergeometric2F1.
Now using Collect and Simplify,
s[d_, p_, q_][g_] = Collect[% /. Gamma[q + 1] -> q!,
Hypergeometric2F1[a_, b_, c_, d_], Simplify]
one has an expression involving a Hypergeometric2F1 that does _not_
produce complex values for reasonable parameter values, and also
evaluates immediately (as a polynomial) for any integer q >= 1. For
example
s[d, p, 2][g] // Factor
> But the simplification that mathematica gives has the following term in it:
>
> Beta[g/g-1, 1/d + 1, Q]
Using FullSimplify (or FunctionExpand) causes the Hypergeometric2F1 to
be rewritten as a Beta function -- but also gives rise to terms such as
(-g)^(-d^(-1))
that are complex for 0 < g < 1 and d > 0.
> Note that g/(g-1) is actually a negative number & the incomplete beta
> function is not defined for negative parameter.
Yes it is! E.g.,
Beta[-1, 1, 2]
> My ultimate goal is to take the derivative of the final expression
> (output of fullsimplify), so I don't mind an approximation if it
> makes the derivative look simple.
Derivative with respect to what? Computing the derivative with respect
to g is straightforward and not all that complicated. I assume that you
are interested in derivatives with respect to g?
Collect[s[d, p, q]'[g], Hypergeometric2F1[a_, b_, c_, d_], Simplify]
(Note that by separating the parameters [d,p,q] from the argument [g],
one can compute the derivative using '. Generally, this separation of
parameters and arguments is a good idea.)
> When I set P=12, you'll see that you get a complex number.
No. E.g.,
s[15, 12, 17][1/2]
Cheers,
Paul
_______________________________________________________________________
Paul Abbott Phone: 61 8 6488 2734
School of Physics, M013 Fax: +61 8 6488 1014
The University of Western Australia (CRICOS Provider No 00126G)
AUSTRALIA http://physics.uwa.edu.au/~paul
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