       Re: FindRoot & NDSolve

• To: mathgroup at smc.vnet.net
• Subject: [mg64672] Re: [mg64650] FindRoot & NDSolve
• From: Pratik Desai <pdesai1 at umbc.edu>
• Date: Sun, 26 Feb 2006 05:07:54 -0500 (EST)
• References: <200602250753.CAA13936@smc.vnet.net>
• Sender: owner-wri-mathgroup at wolfram.com

```Takashi Inoue wrote:

>Hi all,
>
>This is my first post to here.
>I have a problem and want your help.
>
>Mathematica 4 did the following calculation with no pleblem,
>while Mathematica 5(.2)  cannot do it.
>
>FindRoot[
> (f /.NDSolve[ {D[f[x], {x,1}] - 2 x - a == 0, f == 0}, f, {x, -3, 3}
>][]) == 4,
> {a, -10, 10}
>           ]
>
I think FindRoot requires a initial guess in 5.X and you need some kind
of looping for your different values of a

Here are two possible alternatives (that I could think of) using DSolve
and NDSolve

(*Using DSolve (more preferable perhaps because of the closed form nature)*)

TableForm[{#,x/.FindRoot[(f/.DSolve[{D[f[x], {x,1}]== 2 x + #, f ==
0}, f,
for f[x,a]"}}]

(*Using NDSolve  )

Clear[f,x,a]
Table[Reap[NDSolve[{D[f[x], {x,1}]== 2 x + a, f == 0}, f, {x,-3,3},
Method->{EventLocator,
"Event"->f[x]-4,"EventAction":>Sow[{a,x}]}],{a,-10,10,1}]

Hope this helps

Pratik

>Takashi Inoue,Dept. Phys. Sophia University

```

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