Re: Can anybody help?
- To: mathgroup at smc.vnet.net
- Subject: [mg63527] Re: Can anybody help?
- From: "Ray Koopman" <koopman at sfu.ca>
- Date: Tue, 3 Jan 2006 05:24:42 -0500 (EST)
- References: <dpd7hj$qi2$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Kent Holing wrote:
> I have three vecors containg: v1, v2 and v3.
> v1 and v2 has the same length. v3 is shorter than v1.
> All elements of v3 is an element of v1.
> Need to have the corresponding v2 values corresponding to the v3 (= v1) value.
> Know that the elements of v1 and v3 are different. The elements of v2 do not need to different.
> Ex:
> v1={1,2,3,4,5,6,7,8,9}
> v2={10,11,12,22,32,42,53,63,73}
> v3={3,5,8}
> The corresponding v2 values are {11,32,63}
> It easy to write straightforward code to do this.
> But is it really a very elegant/short way (one-liner?) of doing this in Mathematica?
> Kent Holing
Pick[v2,MemberQ[v3,#]&/@v1]