Re: Can anybody help?
- To: mathgroup at smc.vnet.net
- Subject: [mg63530] Re: [mg63519] Can anybody help?
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Wed, 4 Jan 2006 03:17:07 -0500 (EST)
- Reply-to: hanlonr at cox.net
- Sender: owner-wri-mathgroup at wolfram.com
v1={1,2,3,4,5,6,7,8,9};
v2={10,11,12,22,32,42,53,63,73};
v3={3,5,8};
Pick[v2,MemberQ[v3,#]&/@v1]
{12,32,63}
Bob Hanlon
>
> From: Kent Holing <KHO at statoil.com>
To: mathgroup at smc.vnet.net
> Date: 2006/01/03 Tue AM 01:26:35 EST
> Subject: [mg63530] [mg63519] Can anybody help?
>
> I have three vecors containg: v1, v2 and v3.
> v1 and v2 has the same length. v3 is shorter than v1.
> All elements of v3 is an element of v1.
> Need to have the corresponding v2 values corresponding to the v3 (= v1)
value.
> Know that the elements of v1 and v3 are different. The elements of v2 do
not need to different.
> Ex:
> v1={1,2,3,4,5,6,7,8,9}
> v2={10,11,12,22,32,42,53,63,73}
> v3={3,5,8}
> The corresponding v2 values are {11,32,63}
> It easy to write straightforward code to do this.
> But is it really a very elegant/short way (one-liner?) of doing this in
Mathematica?
> Kent Holing
>
>