Mathematica 9 is now available
Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2006
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2006

[Date Index] [Thread Index] [Author Index]

Search the Archive

rules for using functions as basis vectors

  • To: mathgroup at smc.vnet.net
  • Subject: [mg67064] rules for using functions as basis vectors
  • From: Kenny Stephens <kstephens at hsutx.edu>
  • Date: Thu, 8 Jun 2006 04:53:58 -0400 (EDT)
  • Sender: owner-wri-mathgroup at wolfram.com

I am trying to establish some rules to use a triad of functions as a
triad of basis vectors (i.e., Frenet-Seret formalism). I have achieved
most of the desired functionality but I can not get Mathematica to
properly expand dot products across parantheses. Here is my code.

(* define the tangent vector of the curve r[u] *)
r /: D[r[u_], u_] := t[u];

(* define the dot product relations between the triad vectors *)
{t /: t[u_].t[u_] := 1, t /: t[u_].n[u_] := 0, t /: t[u_].b[u_] := 0,
 n /: n[u_].t[u_] := 0, n /: n[u_].n[u_] := 1, n /: n[u_].b[u_] := 0,
 b /: b[u_].t[u_] := 0, b /: b[u_].n[u_] := 0, b /: b[u_].b[u_] := 1};

(* define the Frenet-Seret relations *)
{Derivative[1][t][u_] := \[Kappa][u] n[u],
 Derivative[1][n][u_] := \[Tau][u] b[u] - \[Kappa][u] t[u],
 Derivative[1][b][u_] := -\[Tau][u] n[u]};

(* how to distribute the triad vectors across multiplication *)
{b /: Dot[b[u_], Times[a_, f_]] := Dot[b[u], ExpandAll[Times[a, f]]],
 t /: Dot[t[u_], Times[a_, f_]] := Dot[t[u], ExpandAll[Times[a, f]]],
 n /: Dot[n[u_], Times[a_, f_]] := Dot[n[u], ExpandAll[Times[a, f]]]};

(* how to distribute the dot product across additions *)
{b /: Dot[b[u_], Plus[y_, z_]] := 
      Dot[b[u], ExpandAll[y]] + Dot[b[u], ExpandAll[z]],
 n /: Dot[n[u_], Plus[y_, z_]] := 
      Dot[n[u], ExpandAll[y]] + Dot[n[u], ExpandAll[z]],
 t /: Dot[t[u_], Plus[y_, z_]] := 
      Dot[t[u], ExpandAll[y]] + Dot[t[u], ExpandAll[z]]};

(* how to neglect the curvature and torsion from dot products *)
{b /: Dot[b[u_], \[Tau][u_]] := 0, b /: Dot[\[Tau][u_], b[u_]] := 0,
 t /: Dot[t[u_], \[Tau][u_]] := 0, t /: Dot[\[Tau][u_], t[u_]] := 0,
 n /: Dot[n[u_], \[Tau][u_]] := 0, n /: Dot[\[Tau][u_], n[u_]] := 0};
{b /: Dot[b[u_], \[Kappa][u_]] := 0, b /: Dot[\[Kappa][u_], b[u_]] := 0,
 t /: Dot[t[u_], \[Kappa][u_]] := 0, t /: Dot[\[Kappa][u_], t[u_]] := 0,
 n /: Dot[n[u_], \[Kappa][u_]] := 0, n /: Dot[\[Kappa][u_], n[u_]] :=0};

(* how to distribute dot products across multiplication of several *)
(* terms; this is necessary to avoid exceeding iteration limits *)
{b /: Dot[b[u_], Times[a_, b[u_], g_[u_]]] := a g[u] b[u].b[u], 
 b /: Dot[b[u_], Times[a_, t[u_], g_[u_]]] := a g[u] b[u].t[u], 
 b /: Dot[b[u_], Times[a_, n[u_], g_[u_]]] := a g[u] b[u].n[u]};
{t /: Dot[t[u_], Times[a_, b[u_], g_[u_]]] := a g[u] t[u].b[u], 
 t /: Dot[t[u_], Times[a_, t[u_], g_[u_]]] := a g[u] t[u].t[u], 
 t /: Dot[t[u_], Times[a_, n[u_], g_[u_]]] := a g[u] t[u].n[u]};
{n /: Dot[n[u_], Times[a_, b[u_], g_[u_]]] := a g[u] n[u].b[u], 
 n /: Dot[n[u_], Times[a_, t[u_], g_[u_]]] := a g[u] n[u].t[u], 
 n /: Dot[n[u_], Times[a_, n[u_], g_[u_]]] := a g[u] n[u].n[u]};

Now the following expression works (copied straight from Mathematica):
\!\(b[u\_1] . \( (t[u\_1] - n[u\_1]\ u\_3\ \[Tau][u\_1] 
                 + u\_2\ \((\(-t[u\_1]\)\ \[Kappa][u\_1] 
                 + b[u\_1]\ \[Tau][u\_1]) \))\) \)
giving the correct result
\!\(u\_2\ \[Tau][u\_1]\)

However, exchanging the order of the arguments to the dot product does
not work (having b[u\_1] on the right side of the dot product instead of
the left). Mathematica simply returns the input. Furthermore, if one
dots the argument in parantheses with itself, the input is likewise
returned.

What am I missing? Any suggestions on how to get this to work would be
greatly appreciated.

Thanks.


  • Prev by Date: Re: Two questions (1) Sollve and (2) Precision
  • Next by Date: Or in a Select question
  • Previous by thread: Re: Using a list as a variable
  • Next by thread: Re: rules for using functions as basis vectors